我在回答 Python 測驗(yàn)時(shí)遇到了一些問題：給定兩個(gè)數(shù) X 和 Y，編寫一個(gè)函數(shù)：返回 X 和 Y 之間的偶數(shù)，如果 X 大于 Y，否則返回 x 和 y 之間的奇數(shù)例如，取整數(shù) 10 和 2 。該函數(shù)將返回 2 到 10 之間的所有偶數(shù)。我真的很感激一些幫助，因?yàn)槲疫€是個(gè)新手這是我的代碼：def number_game(x,y): num = range(x,y) for e in num: if x > y: return e%2 == 0 else: return e%3 == 0以下是測試用例：test.assert_equals(number_game(2,12), [3, 5, 7, 9, 11])test.assert_equals(number_game(0,0), [])test.assert_equals(number_game(2,12), [3, 5, 7, 9, 11])test.assert_equals(number_game(200,180), [180, 182, 184, 186, 188, 190, 192, 194, 196, 198])test.assert_equals(number_game(180,200), [181, 183, 185, 187, 189, 191, 193, 195, 197, 199])
3 回答
FFIVE
TA貢獻(xiàn)1797條經(jīng)驗(yàn) 獲得超6個(gè)贊
使用列表推導(dǎo)式的更 Pythonic 方式
def number_game(x,y):
if x > y:
return [n for n in range(y,x) if n%2==0]
elif y==x:
return []
else:
return [n for n in range(x,y) if n%2!=0]
開滿天機(jī)
TA貢獻(xiàn)1786條經(jīng)驗(yàn) 獲得超13個(gè)贊
使用Generators（yield關(guān)鍵字）查看解決方案
def number_game(x,y):
num = range(min(x,y),max(x,y))
for e in num:
if x > y and e%2 == 0:
yield e
elif x < y and e%2 != 0:
yield e
# you have to materialize generators to lists before comparing them with lists
print(list(number_game(2,12)) == [3, 5, 7, 9, 11])
print(list(number_game(0,0)) == [])
print(list(number_game(2,12)) == [3, 5, 7, 9, 11])
print(list(number_game(200,180)) == [180, 182, 184, 186, 188, 190, 192, 194, 196, 198])
print(list(number_game(180,200)) == [181, 183, 185, 187, 189, 191, 193, 195, 197, 199])
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