我有一個(gè)對(duì)象數(shù)組，我想避免使用特定鍵值重復(fù)值。這是一個(gè)對(duì)象數(shù)組。   var dept =  [    {  "department": [    { "userName": "cds",      "userId": "33",      "userFirstname": "Chef",      "userLastname": "Jone"    },    {      "userName": "asset1",      "userId": "27",      "userFirstname": "Asset",      "userLastname": "Ann "    }  ],  "comment": "",  "doc": null},{  "department": [    {       "userName": "audit1",      "userId": "32",      "userFirstname": "Audit",      "userLastname": "Kim"    },    { "userName": "cds",      "userId": "33",      "userFirstname": "Chef",      "userLastname": "Jone"    }  ],  "comment": "",  "doc": null    } ];我試圖通過(guò) javascript 返回不重復(fù)的對(duì)象。但結(jié)果似乎不同。我可以從一個(gè)對(duì)象數(shù)組中返回值。但是，我覺(jué)得從數(shù)組數(shù)組中提取值很困難。如何分配數(shù)組的過(guò)濾器數(shù)組？任何幫助，將不勝感激。提前致謝。   function getUnique(dept, comp) {   const unique = dept   .map(e => e[comp]) // store the keys of the unique objects.map((e, i, final) => final.indexOf(e) === i && i)// eliminate the dead keys & store unique objects.filter(e => dept[e]).map(e => dept[e]);  return unique;  }return getUnique(dept,'userName');我會(huì)得到結(jié)果 [{  "department": [    { "userName": "cds",      "userId": "33",      "userFirstname": "Chef",      "userLastname": "Jone"    },    {      "userName": "asset1",      "userId": "27",      "userFirstname": "Asset",      "userLastname": "Ann "    }  ],  "comment": "",  "doc": null},{  "department": [    {       "userName": "audit1",      "userId": "32",      "userFirstname": "Audit",      "userLastname": "Kim"    }   ],  "comment": "",  "doc": null    }  ];然而，我得到了結(jié)果   [    {"department": [ { "userName": "cds",    "userId": "33",    "userFirstname": "Chef",    "userLastname": "Jone" }, {      "userName": "asset1",      "userId": "27",      "userFirstname": "Asset",      "userLastname": "Ann "  }],"comment": "","doc": null  }]