我正在尋找一種使用加號(hào)和減號(hào)按鈕更新或驗(yàn)證動(dòng)態(tài)輸入組輸入的最小值和最大值的方法。這是我到目前為止所做的：HTML <div class="center"> <div class="input-group"> <span class="input-group-btn"> <button type="button" class="btn btn-danger btn-number" data-type="minus" data-field="numbergroup'+thisgroupid+'id'+buttonid+'max&'+row.max+'""> <span class="glyphicon glyphicon-minus"></span> </button> </span> <input type="text" name="numbergroup'+thisgroupid+'id'+buttonid+'max&'+row.max+'"" value="0" class="form-control input-number" min="'+row2.min+'" max="'+row2.max+'"> <span class="input-group-btn"> <button type="button" class="btn btn-success btn-number" data-type="plus" data-field="numbergroup'+thisgroupid+'id'+buttonid+'max&'+row.max+'""> <span class="glyphicon glyphicon-plus"></span> </button> </span> </div></div>JS $('.btn-number').click(function(e){e.preventDefault();fieldName = $(this).attr('data-field');console.log(fieldName) var grpmax = fieldName.split('&')[1]; console.log(grpmax)type = $(this).attr('data-type'); console.log(type)var input = $("input[name='"+fieldName+"']");var currentVal = parseInt(input.val());if (!isNaN(currentVal)) { if(type == 'minus') { if(currentVal > input.attr('min')) { input.val(currentVal - 1).change(); } if(parseInt(input.val()) == input.attr('min')) { $(this).attr('disabled', true); } } else if(type == 'plus') { if(currentVal < input.attr('max')) { input.val(currentVal + 1).change(); } if(parseInt(input.val()) == input.attr('max')) { $(this).attr('disabled', true); } }} else { input.val(0);}});$('.input-number').focusin(function(){ $(this).data('oldValue', $(this).val());});$('.input-number').change(function() {minValue = parseInt($(this).attr('min'));maxValue = parseInt($(this).attr('max'));valueCurrent = parseInt($(this).val());我正在為每個(gè)輸入字段設(shè)置min和max值，但我沒有為將要?jiǎng)?chuàng)建的每個(gè)輸入組設(shè)置min和max值。我需要設(shè)置組最大值或添加驗(yàn)證以檢查組的總值是否小于或等于grpmax
動(dòng)態(tài)設(shè)置輸入組最小值和最大值
眼眸繁星
2021-06-15 12:21:01
