我有一個(gè)對(duì)象數(shù)組，我試圖在 php 中壓縮它們。這是我的數(shù)組$proposedStudentFeeCollection = [{"id":1,"student_id":"1","feeType_id":"2","proposed_fee":"5000"},{"id":2,"student_id":"1","feeType_id":"1","proposed_fee":"5000"},{"id":3,"student_id":"1","feeType_id":"1","proposed_fee":"2000"},{"id":4,"student_id":"1","feeType_id":"2","proposed_fee":"15000"},{"id":5,"student_id":"1","feeType_id":"2","proposed_fee":"5000"},{"id":6,"student_id":"1","feeType_id":"11","proposed_fee":"9000"},{"id":7,"student_id":"1","feeType_id":"1","proposed_fee":"20000"},{"id":8,"student_id":"1","feeType_id":"16","proposed_fee":"1000"}]我希望得到一個(gè)“新的”簡化陣列，它給了我總結(jié)的一樣feeType_id，像這樣[{"id":1,"student_id":"1","feetype_id":"1","proposed_fee":"27000"},{"id":2,"student_id":"1","feetype_id":"2","proposed_fee":"25000"},{"id":3,"student_id":"1","feetype_id":"11","proposed_fee":"9000"},{"id":4,"student_id":"1","feetype_id":"16","proposed_fee":"1000"}]我正在嘗試這樣做$myArray = array();for($i=0; $i<2; $i++){    $tempObject = $proposedStudentFeeCollection[$i];    for($j=count($proposedStudentFeeCollection)-1; $j >= 0; $j--) {        if($tempObject->feetype_id == $proposedStudentFeeCollection[$j]->feetype_id){            $tempObject->proposed_fee += $proposedStudentFeeCollection[$j]->proposed_fee;            unset($proposedStudentFeeCollection[$j]);        }    }    $myArray[] = $tempObject;}return $myArray;但我沒有得到答案。什么是正確的方法？