我需要解組的 XML 格式如下：data := `<table>    <name>        <code>23764</code>        <name>Smith, Jane</name>    </name>    <name>        <code>11111</code>        <name>Doe, John</name>    </name></table>`我嘗試了以下結(jié)構(gòu)和代碼無濟(jì)于事：type Customers struct {    XMLName xml.Name `xml:"table"`    Custs []Customer}type Customer struct {    XMLName xml.Name `xml:"name"`    Code string `xml:"code"`    Name string `xml:"name"`}...var custs Customerserr := xml.Unmarshal([]byte(data), &custs)if err != nil {    fmt.Printf("error: %v", err)    return}fmt.Printf("%v", custs)for _, cust := range custs.Custs {    fmt.Printf("Cust:\n%v\n", cust)}范圍沒有打印出來，打印custs只給我{{ table} []}