支持我們有一個像這樣的字符串：s = u'apple banana lemmon (hahaha) dog cat whale (hehehe) red blue black'我要創(chuàng)建以下列表：including = ['hahaha', 'hehehe']
excluding = ['apple banana lemmon (', ') dog cat whale (', ') red blue black']第一個列表是直接使用正則表達(dá)式：including = re.findall('\((.*?)\)',s)但是我無法為其他列表獲得類似的信息。你可以幫幫我嗎？先感謝您！！
3 回答
MM們
TA貢獻(xiàn)1886條經(jīng)驗 獲得超2個贊
excluding = re.split('|'.join(including), s)對于您知道包含信息將不包含特殊字符或正則表達(dá)式定義的簡單情況。
如果您不確定是否會出現(xiàn)這種情況：
re.split('|'.join(map(re.escape, including)), s)這將轉(zhuǎn)義特殊的正則表達(dá)式字符，否則將導(dǎo)致re.split函數(shù)功能異常
叮當(dāng)貓咪
TA貢獻(xiàn)1776條經(jīng)驗 獲得超12個贊
使用正則表達(dá)式
a = re.findall('\)?[^()]*\(?', s)
excluded = a[::2]
included = a[1::2]
print(included, excluded, sep='\n')
['hahaha', 'hehehe', '']
['apple banana lemmon (', ') dog cat whale (', ') red blue black']
照顧空字符串
a = re.findall('\)?[^()]*\(?', s)
excluded = [*filter(bool, a[::2])]
included = [*filter(bool, a[1::2])]
print(included, excluded, sep='\n')
['hahaha', 'hehehe']
['apple banana lemmon (', ') dog cat whale (', ') red blue black']
沒有正則表達(dá)式
from itertools import cycle
def f(s):
c = cycle('()')
a = {'(': 1, ')': 0}
while s:
d = next(c)
i = s.find(d)
if i > -1:
j = a[d]
yield d, s[:i + j]
s = s[i + j:]
else:
yield d, s
break
included = []
excluded = []
for k, v in f(s):
if k == '(':
excluded.append(v)
else:
included.append(v)
print(included, excluded, sep='\n')
['hahaha', 'hehehe']
['apple banana lemmon (', ') dog cat whale (', ') red blue black']
相同想法但不覆蓋 s
from itertools import cycle
def f(s):
c = cycle('()')
a = {'(': 1, ')': 0}
j = 0
while True:
d = next(c)
i = s.find(d, j)
if i > -1:
k = a[d]
yield d, s[j:i + k]
j = i + k
else:
yield d, s[j:]
break
included = []
excluded = []
for k, v in f(s):
if k == '(':
excluded.append(v)
else:
included.append(v)
print(included, excluded, sep='\n')
['hahaha', 'hehehe']
['apple banana lemmon (', ') dog cat whale (', ') red blue black']
胡子哥哥
TA貢獻(xiàn)1825條經(jīng)驗 獲得超6個贊
您可以使用正向后視和正向前瞻來拆分括號之間的單詞：
>>> re.split(r'(?<=\().*?(?=\))', s)
['apple banana lemmon (', ') dog cat whale (', ') red blue black']
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