我有一個(gè)列表，類似這樣的“ List <Block>”。我想要的是獲得一個(gè)與列表中的塊相同的塊，而不是列表中的對象。并用塊修改圓頂并獲得另一個(gè)。但是問題是，在獲取了三次塊（列表的長度為3）之后，第四個(gè)塊已經(jīng)被修改。我嘗試了我所知道的所有方法，甚至使用“ new”，它只是將對象添加到列表中，而不是同一對象。那么如何解決呢？這是我的一些代碼：//This is the list which length is 3private List<BlockType> blocks;//At the beginning it was like this but not work//private List<Block> blocks;//In a function to get a block type randomlyint blockNum = rand.Next(0, 3); //rand is a Random typethis.cBlock = new Block(blocks[blockNum]); //cBlock is object which I use to do something about the block//The class Block goes toclass Block{ private List<Rectangle> _block; public List<Rectangle> block { get { return _block; } } private int _blockNum; public int blockNum { get { return _blockNum; } } public Block() { } public Block(int blockNum, List<Rectangle> block) { this._block = block; this._blockNum = blockNum; } public Block(BlockType block) { this._block = block.block; this._blockNum = block.blockNum; }}//And the BlockType is what I tried but does not workclass BlockType{ private List<Rectangle> _block; public List<Rectangle> block { get { return _block; } } private int _blockNum; public int blockNum { get { return _blockNum; } } public BlockType() { } public BlockType(int blockNum, List<Rectangle> block) { this._block = block; this._blockNum = blockNum; }}
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桃花長相依
TA貢獻(xiàn)1860條經(jīng)驗(yàn) 獲得超8個(gè)贊
編輯：
OP被誤以為是一個(gè)新實(shí)例，因?yàn)樗鼪]有在復(fù)制構(gòu)造函數(shù)中克隆，而是被簡單地分配了，因此Block被引出了一個(gè)實(shí)例，因此導(dǎo)致兩個(gè)唯一的實(shí)例引用同一個(gè)實(shí)例。List<Block>List<Rectangle>BlockList<Rectangle>
在這種情況下，正確的副本構(gòu)造函數(shù)將是：
public Block(Block originalBlock)
{
this._block = new List<Rectangle>(originalBlock.block);
this._blockNum = originalBlock.blockNum;
}
在Rectangle類中需要類似的復(fù)制構(gòu)造函數(shù)。
這應(yīng)該為您工作：
public class Block
{
private List<Rectangle> _block;
public List<Rectangle> block
{
get { return _block; }
}
private int _blockNum;
public int blockNum
{
get { return _blockNum; }
}
// Copy constructor
public Block(Block originalBlock)
{
// IMPORTANT: This does not create a new List<Rectangle>! See EDIT
this._block = originalBlock.block;
this._blockNum = originalBlock.blockNum;
}
}
用法：
Block originalBlock = new Block();
// Returns a new instance of Block with similar member data.
Block copiedBlock = new Block(originalBlock);
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