當(dāng)嘗試使用php和mysql登錄此應(yīng)用程序時(shí)，將Authorization failed顯示該應(yīng)用程序中使用的錯(cuò)誤。閱讀php_error.log時(shí)顯示：[05.05.2019 03:31:51 UTC] PHP注意：未定義的索引：結(jié)果在第43行的/Applications/MAMP/htdocs/iReporter/api.php中[05-May-2019 03:31:51 UTC] PHP警告：count（）：參數(shù)必須是在第43行的/Applications/MAMP/htdocs/iReporter/api.php中實(shí)現(xiàn)Countable的數(shù)組或?qū)ο蟮卿浌δ?/login APIfunction login($user, $pass) {// try to match a row in the "login" table for the given username and password$result = query("SELECT IdUser, username FROM login WHERE username='%s' AND pass='%s' limit 1", $user, $pass);//Line 43if (count($result['result'])>0) {    // a row was found in the database for username/pass combination    // save a simple flag in the user session, so the server remembers that the user is authorized    $_SESSION['IdUser'] = $result['result'][0]['IdUser'];    // print out the JSON of the user data to the iPhone app; it looks like this:    // {IdUser:1, username: "Name"}    print json_encode($result);//editvar_dump($result);} else {    // no matching username/password was found in the login table    errorJson('Authorization failed');}}該應(yīng)用程序用于讓用戶無縫登錄，但突然停止工作，而無需對(duì)代碼進(jìn)行任何更改。即使未更改的備份文件也收到相同的錯(cuò)誤。如何更改代碼以允許用戶成功登錄？更新：index.php。應(yīng)用程序訪問功能的主文件switch ($_POST['command']) {case "login":    login($_POST['username'], $_POST['password']);     break;解決了更改了iOS應(yīng)用程序，以將密碼而不是固定密碼發(fā)布到數(shù)據(jù)庫，因?yàn)樗趧?chuàng)建錯(cuò)誤。