假設我有字符串數(shù)組（但它也可以與數(shù)字數(shù)組一起使用）。我想在它們上面創(chuàng)建一個Map對象，以2的值作為鍵，其他的值作為鍵，但是基本上是要建立一種關系。在下一步之后，將根據(jù)2個對象數(shù)組創(chuàng)建一個Map，但這有點復雜。不幸的是，到目前為止，我的方法不起作用（因為要花幾個小時才能使它起作用），因為我獲得了第二個值，即“ Map Iterator”或者“ Objects Arrays”。let pairsMap = new Map(); let productsMap = new Map();let engWords = ['house','gift','zoo','tidy','flat','to play',' to see','boy','ice cream']let itaWords = ['casa','regalo','zoo','ordinato','appartamento','giocare','guardare','ragazzo','gelato'] let pairsMap = new Map(); let productsMap = new Map();let products = [{  name: "chair",  inventory: 5,  unit_price: 45.99,  client:'MG Gmbh'},{  name: "table",  inventory: 10,  unit_price: 123.75,  client : "XYZ"},{  name: "sofa",  inventory: 2,  unit_price: 399.50,  client : "MongoDB"}];let clients  =[ {     name:"MG Gmbh",     address: 'Linen street',     country: 'Germany' }, {     name:'XYZ',     address:'Mongomery street',     country: 'USA' }, {     name:'MongoDB',     address: 'NoSQL road',     country: 'UK' }, {    name:'Zeppelin',    address: 'lienestra?e',    country: 'Germany'}];for( val in engWords){      const nk =  engWords[val];      engWords.forEach(function(element) {      const v = pairsMap.values();      pairsMap.set(nk,v);      } )   } for (let [b, z] of pairsMap){     console.log(b, " -> ", z) } function groupBy(objectArray, property) {      return objectArray.reduce(function (acc, obj) {   var key = obj[property];     if (!acc[key]) {        acc[key] = [];     }     acc[key].push(obj);     return acc;     }, {});  }let clients_name = console.log(groupedClients); for( val in groupedClients){       const nk =  groupedClients[val];       products.forEach(function(element) {           const v = productsMap.values();           productsMap.set(nk,v);          } )   }這是我想得到的結果（來自engWords和itaWords）house  ->  casa gift  ->  regalo zoo  ->  zoo tidy  ->  ordinato flat  ->  appartamento to play  ->  giocare to see  ->  guardare boy  ->  ragazzo ice cream  ->  gelato