我有兩個JSON對象，如果鍵和值匹配，則想返回'true'值。d1和d2的所有三個值都應(yīng)匹配。var d1 = [{"deviceid":"867874031097770","simno":"232ff33","slot":"1"},{"deviceid":"86787403100","simno":"ss343433","slot":"2"}];var d2 = {"deviceid":"867874031097770","simno":"232ff33","slot":"1"};我嘗試使用以下代碼，但不適用于JSON值數(shù)組。function equals ( x, y ) {    // If both x and y are null or undefined and exactly the same    if ( x === y ) {        return true;    }    // If they are not strictly equal, they both need to be Objects    if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) {        return false;    }    // They must have the exact same prototype chain, the closest we can do is    // test the constructor.    if ( x.constructor !== y.constructor ) {        return false;    }    for ( var p in x ) {        // Inherited properties were tested using x.constructor === y.constructor        if ( x.hasOwnProperty( p ) ) {            // Allows comparing x[ p ] and y[ p ] when set to undefined            if ( ! y.hasOwnProperty( p ) ) {                return false;            }            // If they have the same strict value or identity then they are equal            if ( x[ p ] === y[ p ] ) {                continue;            }            // Numbers, Strings, Functions, Booleans must be strictly equal            if ( typeof( x[ p ] ) !== "object" ) {                return false;            }            // Objects and Arrays must be tested recursively            if ( !equals( x[ p ],  y[ p ] ) ) {                return false;            }        }    }    for ( p in y ) {        // allows x[ p ] to be set to undefined        if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) ) {            return false;        }    }    return true;}