如今，我嘗試根據(jù)一個(gè)公共密鑰合并兩個(gè)jon。我在一個(gè)公共字段中輸入了兩個(gè)不同的JSON，我想基于公共密鑰合并兩個(gè)JSON的數(shù)據(jù)。兩種JSON之間的一種sql連接。JSON源自此代碼func Dati_plus(c *gin.Context) {oracle, err := http.Get("http://XXXX/XXX")    if err != nil {            panic(err)    }defer oracle.Body.Close()mysql, err := http.Get("http://XXXX/XXX")if err != nil {        panic(err)}defer mysql.Body.Close()oracleJSON, err := ioutil.ReadAll(oracle.Body)if err != nil {        panic(err)}mysqlJSON, err := ioutil.ReadAll(mysql.Body)if err != nil {        panic(err)}var oracleOUT map[string]interface{}var mysqlOUT map[string]interface{}json.Unmarshal([]byte(oracleJSON), &oracleOUT)json.Unmarshal([]byte(mysqlJSON), &mysqlOUT)a := map[string]interface{}{"result":mysqlOUT["result"]}b := map[string]interface{}{"result":oracleOUT["result"]}輸入中的JSON具有這種形式{"count":2,"result":[{"DESC":"2","NOMEmy":"PIPPO","COGNOMEmy":"PIPPO"},{"DESC":"7","NOMEmy":"PIPPO","COGNOMEmy":"PIPPO"}]{"count":2,"result":[{"DESC":"2","COS":"PIPPO","ROS":"PIPPO"},{"DESC":"7","COS":"PIPPO","ROS":"PIPPO"},{"DESC":"60","COS":"PIPPO","ROS":"PIPPO"}]如果我有兩個(gè)這樣的json函數(shù)的結(jié)果應(yīng)該是{"count":2,"result":[{"DESC":"2","COS":"PIPPO","ROS":"PIPPO","NOMEmy":"PIPPO","COGNOMEmy":"PIPPO"},{"DESC":"7","COS":"PIPPO","ROS":"PIPPO","NOMEmy":"PIPPO","COGNOMEmy":"PIPPO"},{"DESC":"60","COS":"PIPPO","ROS":"PIPPO"}]如果可以幫助的話，這是我用于在兩個(gè)單值JSON之間進(jìn)行合并的函數(shù)，但是我無法以正確的方式對(duì)其進(jìn)行修改    func merge(dst, src map[string]interface{}, depth int) map[string]interface{} {    if depth > MaxDepth {        panic("Troppo Lungo")    }    for key, srcVal := range src {        if dstVal, ok := dst[key]; ok {            srcMap, srcMapOk := mapify(srcVal)            dstMap, dstMapOk := mapify(dstVal)            if srcMapOk && dstMapOk {                srcVal = merge(dstMap, srcMap, depth+1)            }        }        dst[key] = srcVal    }    return dst}請(qǐng)幫我。謝謝