我有以下列表列表：animals = [('dog', 'cat'), ('mouse', 'bird')]我想將其簡化為：animals = ['dog', 'cat', 'mouse', 'bird']有沒有比做這樣的事情更簡單的方法來獲得上面的結(jié)果：animals = [('dog', 'cat'), ('mouse', 'bird')]final = []for a in animals: final.append(a[0]) final.append(a[1])print final
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qq_花開花謝_0
TA貢獻(xiàn)1835條經(jīng)驗(yàn) 獲得超7個(gè)贊
您可以使用itertools.chain.from_iterable：
>>> from itertools import chain
>>> list(chain.from_iterable(animals))
['dog', 'cat', 'mouse', 'bird']
或嵌套的list comprehension：
>>> [anim for item in animals for anim in item]
['dog', 'cat', 'mouse', 'bird']
對(duì)于小型列表，請(qǐng)使用列表理解版本，否則請(qǐng)使用itertools.chain.from_iterable。
>>> animals = [('dog', 'cat'), ('mouse', 'bird')]
>>> %timeit list(chain.from_iterable(animals))
100000 loops, best of 3: 2.31 us per loop
>>> %timeit [anim for item in animals for anim in item]
1000000 loops, best of 3: 1.13 us per loop
>>> animals = [('dog', 'cat'), ('mouse', 'bird')]*100
>>> %timeit list(chain.from_iterable(animals))
10000 loops, best of 3: 31.5 us per loop
>>> %timeit [anim for item in animals for anim in item]
10000 loops, best of 3: 73.7 us per loop
>>> animals = [('dog', 'cat'), ('mouse', 'bird')]*1000
>>> %timeit list(chain.from_iterable(animals))
1000 loops, best of 3: 296 us per loop
>>> %timeit [anim for item in animals for anim in item]
1000 loops, best of 3: 733 us per loop
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