嘗試重構(gòu)collectionsQuery中的keywordAlt位def countSubject(genres):    for keyword in genres:          keywordAlt = '%'+keyword+'%'        collectionsQuery = Collection.select().join(Subject).where(Subject.name ** keywordAlt, Subject.name != 'librivox', Subject.name != 'spoken',  Subject.name != 'audiobook', Collection.downloads > 50)        if collectionsQuery.count() > 5:            print keyword, collectionsQuery.count()我正在重構(gòu)此代碼段，并且想要首先刪除keywordAlt位，并將文本包含在我的查詢中。然而        collectionsQuery = Collection.select().join(Subject).where(Subject.name ** '%'+keyword+'%', Subject.name != 'librivox', Subject.name != 'spoken',  Subject.name != 'audiobook', Collection.downloads > 50)但是，使用第二種方法，它可以匹配所有內(nèi)容。        collectionsQuery = Collection.select().join(Subject).where(Subject.name ** %keyword%, Subject.name != 'librivox', Subject.name != 'spoken',  Subject.name != 'audiobook', Collection.downloads > 50)這被解釋為對(duì)“關(guān)鍵字”的通配符搜索正確的語法是什么？