我想從字符串中匹配可能的名稱。名稱應(yīng)為2-4個單詞，每個單詞包含3個或更多字母，所有單詞均大寫。例如，給定以下字符串列表：Her name is Emily.I work for Surya Soft.I sent an email for Ery Wulandari.Welcome to the Link Building Partner program!我想要一個返回的正則表達(dá)式：NoneSurya SoftEry WulandariLink Building Partner目前這是我的代碼：data = [ 'Her name is Emily.', 'I work for Surya Soft.', 'I sent an email for Ery Wulandari.', 'Welcome to the Link Building Partner program!']for line in data: print re.findall('(?:[A-Z][a-z0-9]{2,}\s+[A-Z][a-z0-9]{2,})', line)它適用于前三行，但不適用于最后一行。
3 回答
森林海
TA貢獻(xiàn)2011條經(jīng)驗 獲得超2個贊
您可以使用：
re.findall(r'((?:[A-Z]\w{2,}\s*){2,4})', line)它可能會添加一個尾隨空格，可以用 .strip()
Qyouu
TA貢獻(xiàn)1786條經(jīng)驗 獲得超11個贊
非正則表達(dá)式解決方案：
from string import punctuation as punc
def solve(strs):
words = [[]]
for i,x in enumerate(strs.split()):
x = x.strip(punc)
if x[0].isupper() and len(x)>2:
if words[-1] and words[-1][-1][0] == i-1:
words[-1].append((i,x))
else:
words.append([(i,x)])
names = [" ".join(y[1] for y in x) for x in words if 2 <= len(x) <= 4]
return ", ".join(names) if names else None
data = [
'Her name is Emily.',
'I work for Surya Soft.',
'I sent an email for Ery Wulandari.',
'Welcome to the Link Building Partner abc Fooo Foo program!'
]
for x in data:
print solve(x)
輸出：
None
Surya Soft
Ery Wulandari
Link Building Partner, Fooo Foo
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