我有一個NSURL：serverCall？x = a＆y = b＆z = c獲取y值的最快，最有效的方法是什么？謝謝
3 回答
忽然笑
TA貢獻1806條經(jīng)驗 獲得超5個贊
我很確定您必須自己解析它。但是，還算不錯：
NSString * q = [myURL query];
NSArray * pairs = [q componentsSeparatedByString:@"&"];
NSMutableDictionary * kvPairs = [NSMutableDictionary dictionary];
for (NSString * pair in pairs) {
NSArray * bits = [pair componentsSeparatedByString:@"="];
NSString * key = [[bits objectAtIndex:0] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString * value = [[bits objectAtIndex:1] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
[kvPairs setObject:value forKey:key];
}
NSLog(@"y = %@", [kvPairs objectForKey:@"y"]);
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