該程序之所以死是因為無限遞歸：use std::any::Any;trait Foo {    fn get(&self, index: usize) -> Option<&Any>;}impl Foo for Vec<i32> {    fn get(&self, index: usize) -> Option<&Any> {        Vec::get(self, index).map(|v| v as &Any)    }}fn main() {    let v: Vec<i32> = vec![1, 2, 4];    println!("Results: {:?}", v.get(0))}編譯器本身對此發(fā)出警告：warning: function cannot return without recurring  --> src/main.rs:8:5   |8  |       fn get(&self, index: usize) -> Option<&Any> {   |  _____^ starting here...9  | |         Vec::get(self, index).map(|v| v as &Any)10 | |     }   | |_____^ ...ending here   |   = note: #[warn(unconditional_recursion)] on by defaultnote: recursive call site  --> src/main.rs:9:9   |9  |         Vec::get(self, index).map(|v| v as &Any)   |         ^^^^^^^^^^^^^^^^^^^^^   = help: a `loop` may express intention better if this is on purpose為什么在這種情況下通用調(diào)用語法不起作用？編譯器不明白，我想打電話給Vec::get沒有Foo::get。如果我不想更改函數(shù)名稱，該如何解決？