我正在嘗試將以下兩個數(shù)組合并為一個共享相同密鑰的數(shù)組：第一個數(shù)組：array(3) { [0]=> array(1) { ["Camera1"]=> string(14) "192.168.101.71"}[1]=>array(1) { ["Camera2"]=> string(14) "192.168.101.72"}[2]=>array(1) { ["Camera3"]=> string(14) "192.168.101.74"}}第二個數(shù)組：array(3) { [0]=> array(1) { ["Camera1"]=> string(2) "VT" } [1]=> array(1) { ["Camera2"]=> string(2) "UB" } [2]=> array(1) { ["Camera3"]=> string(2) "FX" }}如您所見，它們共享相同的密鑰（Camera1，Camera2，Camera3等。）這是我嘗試過的： $Testvar = array_merge($NewArrayCam,$IpAddressArray); foreach ($Testvar AS $Newvals){ $cam = array(); foreach($Newvals AS $K => $V){ $cam[] = array($K => $V); }
3 回答
阿晨1998
TA貢獻2037條經(jīng)驗 獲得超6個贊
this would be one of the soluion:
function array_merge_custom($array1,$array2) {
$mergeArray = [];
$array1Keys = array_keys($array1);
$array2Keys = array_keys($array2);
$keys = array_merge($array1Keys,$array2Keys);
foreach($keys as $key) {
$mergeArray[$key] = array_merge_recursive(isset($array1[$key])?$array1[$key]:[],isset($array2[$key])?$array2[$key]:[]);
}
return $mergeArray;
}
$array1 = array(
array("Camera1" => "192.168.101.71"),
array("Camera2" => "192.168.101.72"),
array("Camera3" => "192.168.101.74"),
);
$array2 = array(
array("Camera1" => "VT"),
array("Camera2" => "UB"),
array("Camera3" => "FX")
);
echo '<pre>';
print_r(array_merge_custom($array1 , $array2));
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