我有以下課程public class MyClass { private List<MyOtherClass> others;}public class MyOtherClass { private String name;}我有可能看起來像這樣的JSON{ others: { name: "val" }}或這個(gè){ others: [ { name: "val" }, { name: "val" } ]}我希望能夠MyClass對(duì)這兩種JSON格式使用相同的格式。有辦法用Gson做到這一點(diǎn)嗎？
3 回答
慕沐林林
TA貢獻(xiàn)2016條經(jīng)驗(yàn) 獲得超9個(gè)贊
謝謝您提供的三個(gè)杯子！
如果需要多個(gè)類型，則與泛型類型相同：
public class SingleElementToListDeserializer<T> implements JsonDeserializer<List<T>> {
private final Class<T> clazz;
public SingleElementToListDeserializer(Class<T> clazz) {
this.clazz = clazz;
}
public List<T> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
List<T> resultList = new ArrayList<>();
if (json.isJsonArray()) {
for (JsonElement e : json.getAsJsonArray()) {
resultList.add(context.<T>deserialize(e, clazz));
}
} else if (json.isJsonObject()) {
resultList.add(context.<T>deserialize(json, clazz));
} else {
throw new RuntimeException("Unexpected JSON type: " + json.getClass());
}
return resultList;
}
}
并配置Gson：
Type myOtherClassListType = new TypeToken<List<MyOtherClass>>() {}.getType();
SingleElementToListDeserializer<MyOtherClass> adapter = new SingleElementToListDeserializer<>(MyOtherClass.class);
Gson gson = new GsonBuilder()
.registerTypeAdapter(myOtherClassListType, adapter)
.create();
波斯汪
TA貢獻(xiàn)1811條經(jīng)驗(yàn) 獲得超4個(gè)贊
建立三杯的答案，我有以下讓JsonArray直接反序列化為數(shù)組的方法。
static public <T> T[] fromJsonAsArray(Gson gson, JsonElement json, Class<T> tClass, Class<T[]> tArrClass)
throws JsonParseException {
T[] arr;
if(json.isJsonObject()){
//noinspection unchecked
arr = (T[]) Array.newInstance(tClass, 1);
arr[0] = gson.fromJson(json, tClass);
}else if(json.isJsonArray()){
arr = gson.fromJson(json, tArrClass);
}else{
throw new RuntimeException("Unexpected JSON type: " + json.getClass());
}
return arr;
}
用法：
String response = ".......";
JsonParser p = new JsonParser();
JsonElement json = p.parse(response);
Gson gson = new Gson();
MyQuote[] quotes = GsonUtils.fromJsonAsArray(gson, json, MyQuote.class, MyQuote[].class);
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