3 回答

TA貢獻(xiàn)1946條經(jīng)驗(yàn) 獲得超4個(gè)贊
DateTime RoundUp(DateTime dt, TimeSpan d)
{
return new DateTime((dt.Ticks + d.Ticks - 1) / d.Ticks * d.Ticks, dt.Kind);
}
例:
var dt1 = RoundUp(DateTime.Parse("2011-08-11 16:59"), TimeSpan.FromMinutes(15));
// dt1 == {11/08/2011 17:00:00}
var dt2 = RoundUp(DateTime.Parse("2011-08-11 17:00"), TimeSpan.FromMinutes(15));
// dt2 == {11/08/2011 17:00:00}
var dt3 = RoundUp(DateTime.Parse("2011-08-11 17:01"), TimeSpan.FromMinutes(15));
// dt3 == {11/08/2011 17:15:00}

TA貢獻(xiàn)1942條經(jīng)驗(yàn) 獲得超3個(gè)贊
提出了一種不涉及相乘和除法 的解決方案long。
public static DateTime RoundUp(this DateTime dt, TimeSpan d)
{
var modTicks = dt.Ticks % d.Ticks;
var delta = modTicks != 0 ? d.Ticks - modTicks : 0;
return new DateTime(dt.Ticks + delta, dt.Kind);
}
public static DateTime RoundDown(this DateTime dt, TimeSpan d)
{
var delta = dt.Ticks % d.Ticks;
return new DateTime(dt.Ticks - delta, dt.Kind);
}
public static DateTime RoundToNearest(this DateTime dt, TimeSpan d)
{
var delta = dt.Ticks % d.Ticks;
bool roundUp = delta > d.Ticks / 2;
var offset = roundUp ? d.Ticks : 0;
return new DateTime(dt.Ticks + offset - delta, dt.Kind);
}
用法:
var date = new DateTime(2010, 02, 05, 10, 35, 25, 450); // 2010/02/05 10:35:25
var roundedUp = date.RoundUp(TimeSpan.FromMinutes(15)); // 2010/02/05 10:45:00
var roundedDown = date.RoundDown(TimeSpan.FromMinutes(15)); // 2010/02/05 10:30:00
var roundedToNearest = date.RoundToNearest(TimeSpan.FromMinutes(15)); // 2010/02/05 10:30:00

TA貢獻(xiàn)1982條經(jīng)驗(yàn) 獲得超2個(gè)贊
void Main()
{
var date1 = new DateTime(2011, 8, 11, 16, 59, 00);
date1.Round15().Dump();
var date2 = new DateTime(2011, 8, 11, 17, 00, 02);
date2.Round15().Dump();
var date3 = new DateTime(2011, 8, 11, 17, 01, 23);
date3.Round15().Dump();
var date4 = new DateTime(2011, 8, 11, 17, 00, 00);
date4.Round15().Dump();
}
public static class Extentions
{
public static DateTime Round15(this DateTime value)
{
var ticksIn15Mins = TimeSpan.FromMinutes(15).Ticks;
return (value.Ticks % ticksIn15Mins == 0) ? value : new DateTime((value.Ticks / ticksIn15Mins + 1) * ticksIn15Mins);
}
}
結(jié)果:
8/11/2011 5:00:00 PM
8/11/2011 5:15:00 PM
8/11/2011 5:15:00 PM
8/11/2011 5:00:00 PM
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