我正在嘗試使用PHP腳本在同一MySQL數(shù)據(jù)庫中創(chuàng)建2個(gè)表：具有主鍵“ user_id”的表“ user”和具有主鍵“ order_id”和來自“ user”的外鍵“ user_id”的表“ order”表（一對多關(guān)系）。表用戶創(chuàng)建成功，沒有問題：$sql="CREATE TABLE user(    user_id INT UNSIGNED NOT NULL AUTO_INCREMENT,    type ENUM('member','admin') NOT NULL,    username VARCHAR(30) NOT NULL,    email VARCHAR(80) NOT NULL,    pass VARBINARY(32) NOT NULL,    first_name VARCHAR(40) NOT NULL,    last_name VARCHAR(40) NOT NULL,    date_expires DATE NOT NULL,    date_created TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,    date_modified TIMESTAMP NOT NULL DEFAULT '0000-00-00 00:00:00',    PRIMARY KEY (user_id),    UNIQUE (username),    UNIQUE (email)     )ENGINE=InnoDB DEFAULT CHARSET=utf8";但是，我無法創(chuàng)建表順序：$sql="CREATE TABLE order(    order_id INT UNSIGNED NOT NULL AUTO_INCREMENT,    user_id INT UNSIGNED NOT NULL,    transaction_id VARCHAR(19) NOT NULL,    payment_status VARCHAR(15) NOT NULL,    payment_amount DECIMAL(6,2) UNSIGNED NOT NULL,    payment_date_time TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,    PRIMARY KEY (order_id),    FOREIGN KEY (user_id) REFERENCES user (user_id)    )ENGINE=InnoDB DEFAULT CHARSET=utf8";我收到以下錯(cuò)誤：Error creating table: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order( order_id INT UNSIGNED NOT NULL AUTO_INCREMENT, user_id ' at line 1已經(jīng)檢查語法，找不到錯(cuò)誤。您能告訴我出什么問題了嗎？非常感謝。