Kirsteins的答案是正確的，但是為了方便起見(jiàn)，我使用Amol Chaudhari和Rob的建議更新了該答案，他建議使用帶有異步屏障的并發(fā)隊(duì)列來(lái)允許并發(fā)讀取但阻止寫(xiě)入。
我還包裝了一些對(duì)我有用的其他數(shù)組函數(shù)。
public class SynchronizedArray<T> {
private var array: [T] = []
private let accessQueue = dispatch_queue_create("SynchronizedArrayAccess", DISPATCH_QUEUE_CONCURRENT)
public func append(newElement: T) {
dispatch_barrier_async(self.accessQueue) {
self.array.append(newElement)
}
}
public func removeAtIndex(index: Int) {
dispatch_barrier_async(self.accessQueue) {
self.array.removeAtIndex(index)
}
}
public var count: Int {
var count = 0
dispatch_sync(self.accessQueue) {
count = self.array.count
}
return count
}
public func first() -> T? {
var element: T?
dispatch_sync(self.accessQueue) {
if !self.array.isEmpty {
element = self.array[0]
}
}
return element
}
public subscript(index: Int) -> T {
set {
dispatch_barrier_async(self.accessQueue) {
self.array[index] = newValue
}
}
get {
var element: T!
dispatch_sync(self.accessQueue) {
element = self.array[index]
}
return element
}
}
}
UPDATE 這是相同的代碼，為Swift3更新。
public class SynchronizedArray<T> {
private var array: [T] = []
private let accessQueue = DispatchQueue(label: "SynchronizedArrayAccess", attributes: .concurrent)
public func append(newElement: T) {
self.accessQueue.async(flags:.barrier) {
self.array.append(newElement)
}
}
public func removeAtIndex(index: Int) {
self.accessQueue.async(flags:.barrier) {
self.array.remove(at: index)
}
}
public var count: Int {
var count = 0
self.accessQueue.sync {
count = self.array.count
}
return count
}
public func first() -> T? {
var element: T?
self.accessQueue.sync {
if !self.array.isEmpty {
element = self.array[0]
}
}
return element
}
public subscript(index: Int) -> T {
set {
self.accessQueue.async(flags:.barrier) {
self.array[index] = newValue
}
}
get {
var element: T!
self.accessQueue.sync {
element = self.array[index]
}
return element
}
}
}
