這是我的嘗試，它只是我的代碼片段：final double RADIUS = 6371.01;double temp = Math.cos(Math.toRadians(latA)) * Math.cos(Math.toRadians(latB)) * Math.cos(Math.toRadians((latB) - (latA))) + Math.sin(Math.toRadians(latA)) * Math.sin(Math.toRadians(latB)); return temp * RADIUS * Math.PI / 180;我使用這個公式來獲得經(jīng)度和經(jīng)度：x = Deg + (Min + Sec / 60) / 60)
3 回答
猛跑小豬
TA貢獻1858條經(jīng)驗 獲得超8個贊
以上Dommer給出的Java代碼給出了稍微不正確的結果，但如果您正在處理GPS軌道，則會出現(xiàn)小錯誤。以下是Java中Haversine方法的實現(xiàn)，它還考慮了兩點之間的高度差異。
/**
* Calculate distance between two points in latitude and longitude taking
* into account height difference. If you are not interested in height
* difference pass 0.0. Uses Haversine method as its base.
*
* lat1, lon1 Start point lat2, lon2 End point el1 Start altitude in meters
* el2 End altitude in meters
* @returns Distance in Meters
*/
public static double distance(double lat1, double lat2, double lon1,
double lon2, double el1, double el2) {
final int R = 6371; // Radius of the earth
double latDistance = Math.toRadians(lat2 - lat1);
double lonDistance = Math.toRadians(lon2 - lon1);
double a = Math.sin(latDistance / 2) * Math.sin(latDistance / 2)
+ Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2))
* Math.sin(lonDistance / 2) * Math.sin(lonDistance / 2);
double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
double distance = R * c * 1000; // convert to meters
double height = el1 - el2;
distance = Math.pow(distance, 2) + Math.pow(height, 2);
return Math.sqrt(distance);
}
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