我正在嘗試對一組點(diǎn)進(jìn)行透視變換以實(shí)現(xiàn)偏斜效果：http://nuigroup.com/?ACT=28&fid=27&aid=1892_H6eNAaign4Mrnn30Au8d我正在使用下面的圖像進(jìn)行測試，綠色矩形顯示感興趣的區(qū)域。我在想，如果有可能實(shí)現(xiàn)，我希望使用的簡單組合的效果cv::getPerspectiveTransform和cv::warpPerspective。我正在分享我到目前為止所寫的源代碼，但它不起作用。這是結(jié)果圖像因此，有一個(gè)vector<cv::Point>是定義感興趣的區(qū)域，但點(diǎn)不存儲在任何特定的順序載體內(nèi)，這件事情我不能在檢測過程中發(fā)生改變。無論如何，稍后，向量中的點(diǎn)用于定義a RotatedRect，而這又用于組裝cv::Point2f src_vertices[4];，所需的變量之一cv::getPerspectiveTransform()。我對頂點(diǎn)及其組織方式的理解可能是其中一個(gè)問題。我還認(rèn)為使用a RotatedRect不是存儲ROI原始點(diǎn)的最佳方法，因?yàn)樽鴺?biāo)會稍微改變以適應(yīng)旋轉(zhuǎn)的矩形，這并不是很酷。#include <cv.h>#include <highgui.h>#include <iostream>using namespace std;using namespace cv;int main(int argc, char* argv[]){    cv::Mat src = cv::imread(argv[1], 1);    // After some magical procedure, these are points detect that represent     // the corners of the paper in the picture:     // [408, 69] [72, 2186] [1584, 2426] [1912, 291]    vector<Point> not_a_rect_shape;    not_a_rect_shape.push_back(Point(408, 69));    not_a_rect_shape.push_back(Point(72, 2186));    not_a_rect_shape.push_back(Point(1584, 2426));    not_a_rect_shape.push_back(Point(1912, 291));    // For debugging purposes, draw green lines connecting those points     // and save it on disk    const Point* point = &not_a_rect_shape[0];    int n = (int)not_a_rect_shape.size();    Mat draw = src.clone();    polylines(draw, &point, &n, 1, true, Scalar(0, 255, 0), 3, CV_AA);    imwrite("draw.jpg", draw);    // Assemble a rotated rectangle out of that info    RotatedRect box = minAreaRect(cv::Mat(not_a_rect_shape));    std::cout << "Rotated box set to (" << box.boundingRect().x << "," << box.boundingRect().y << ") " << box.size.width << "x" << box.size.height << std::endl;    }有人可以幫我解決這個(gè)問題嗎？