constarr1=['1','2','3','5']constarr2=[{id:'1',},{id:'2',},{id:'3',},{id:'4',}]需求就是arr1跟arr2比較如果arr2得ID等于arr1得話就把等于得arr2放到新數(shù)組中如果有不等于的話把a(bǔ)rr1不等于arr2得值放到一個(gè)新數(shù)組中結(jié)果就是要相等數(shù)組：是arr2id[{id:'1'},{id:'2'},{id:'3'}]不相等數(shù)組：是arr1[5]
有沒(méi)有人遇到過(guò)這個(gè)問(wèn)題哈！js 兩個(gè)數(shù)組比較 拿出相同數(shù)據(jù)跟不相同得值
繁星coding
2019-08-11 14:58:46