如何在django中獲取用戶IP地址？如何在django中獲取用戶的IP？我有這樣的觀點(diǎn)：# Create your viewsfrom django.contrib.gis.utils import GeoIPfrom django.template import RequestContextfrom django.shortcuts import render_to_responsedef home(request):
g = GeoIP()
client_ip = request.META['REMOTE_ADDR']
lat,long = g.lat_lon(client_ip)
return render_to_response('home_page_tmp.html',locals())但我得到這個(gè)錯誤：KeyError at /mypage/
'REMOTE_ADDR'
Request Method: GET Request URL: http://mywebsite.com/mypage/
Django Version: 1.2.4
Exception Type: KeyError
Exception Value:
'REMOTE_ADDR'
Exception Location: /mysite/homepage/views.py in home, line 9
Python Executable: /usr/bin/python Python Version: 2.6.6
Python Path: ['/mysite', '/usr/local/lib/python2.6/dist-packages/flup-1.0.2-py2.6.egg', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/local/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages', '/usr/lib/pymodules/python2.6']
Server time: Sun, 2 Jan 2011 20:42:50 -0600
3 回答
翻過高山走不出你
TA貢獻(xiàn)1875條經(jīng)驗(yàn) 獲得超3個(gè)贊
def get_client_ip(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
ip = x_forwarded_for.split(',')[0]
else:
ip = request.META.get('REMOTE_ADDR')
return ip確保正確配置了反向代理（如果有）（例如，mod_rpaf為Apache安裝）。
注意：以上使用了第一項(xiàng)X-Forwarded-For，但您可能想要使用最后一項(xiàng)（例如，在Heroku的情況下：在Heroku上獲取客戶端的真實(shí)IP地址）
然后將請求作為參數(shù)傳遞給它;
get_client_ip(request)
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