獲取給定日期的正確周數(shù)。我在谷歌上搜索了很多，找到了很多解決方案，但是沒有一個給我正確的2012-12-31周數(shù)。甚至MSDN上的示例(鏈接)失敗。2012-12-31是星期一，所以應(yīng)該是第一周，但是我嘗試的每一種方法都給了我53。以下是我嘗試過的一些方法：來自MDSN庫：DateTimeFormatInfo dfi = DateTimeFormatInfo.CurrentInfo;Calendar cal = dfi.Calendar;return cal.GetWeekOfYear(date, dfi.CalendarWeekRule, dfi.FirstDayOfWeek);解決方案2：return new GregorianCalendar(GregorianCalendarTypes.Localized).GetWeekOfYear(date, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);解決方案3：CultureInfo ciCurr = CultureInfo.CurrentCulture;int weekNum = ciCurr.Calendar.GetWeekOfYear(dtPassed, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);return weekNum;更新當(dāng)日期為2012-12-31時，下面的方法實際上返回1。換句話說，我的問題是我的方法沒有遵循ISO-8601標(biāo)準(zhǔn)。// This presumes that weeks start with Monday.// Week 1 is the 1st week of the year with a Thursday in it.public static int GetIso8601WeekOfYear(DateTime time){
// Seriously cheat. If its Monday, Tuesday or Wednesday, then it'll
// be the same week# as whatever Thursday, Friday or Saturday are,
// and we always get those right
DayOfWeek day = CultureInfo.InvariantCulture.Calendar.GetDayOfWeek(time);
if (day >= DayOfWeek.Monday && day <= DayOfWeek.Wednesday)
{
time = time.AddDays(3);
}
// Return the week of our adjusted day
return CultureInfo.InvariantCulture.Calendar.GetWeekOfYear(time, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);}
3 回答
HUWWW
TA貢獻(xiàn)1874條經(jīng)驗 獲得超12個贊
52周*7天=364天。
美國(星期日->星期六)：2012年-12-30和2012-12-31，每周52周+一周短2天.這總共需要53周的時間。今年的最后兩天(星期日+星期一)組成了他們自己的短短的一周。
歐洲(星期一->星期日)：1月2日(2012-1-2年)是第一個星期一，所以這是第一周的第一天。問問1月1日的周數(shù)，你就會得到52周，因為它被認(rèn)為是2011年最后一周的一部分。
var d = new DateTime(2012, 12, 31);CultureInfo cul = CultureInfo.CurrentCulture;var firstDayWeek = cul.Calendar.GetWeekOfYear(
d,
CalendarWeekRule.FirstDay,
DayOfWeek.Monday);int weekNum = cul.Calendar.GetWeekOfYear(
d,
CalendarWeekRule.FirstDay,
DayOfWeek.Monday);int year = weekNum == 52 && d.Month == 1 ? d.Year - 1 : d.Year;Console.WriteLine("Year: {0} Week: {1}", year, weekNum);CultureInfo cul = CultureInfo.GetCultureInfo("de-DE");- 3 回答
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