如何使用iPhone鍵盤(pán)上的“下一步”按鈕瀏覽所有文本字段？最后一個(gè)文本字段應(yīng)該關(guān)閉鍵盤(pán)。我已經(jīng)設(shè)置了IB按鈕(下一個(gè)/完成)，但現(xiàn)在我被卡住了。我實(shí)現(xiàn)了textFieldShouldRe轉(zhuǎn)折點(diǎn)操作，但是現(xiàn)在下一個(gè)按鈕關(guān)閉鍵盤(pán)。
3 回答
慕哥9229398
TA貢獻(xiàn)1877條經(jīng)驗(yàn) 獲得超6個(gè)贊
所有“可表” UITextFieldS在同一個(gè)父視圖上。 它們的“制表符順序”由Tag屬性定義。
-(BOOL)textFieldShouldReturn:(UITextField*)textField{
NSInteger nextTag = textField.tag + 1;
// Try to find next responder
UIResponder* nextResponder = [textField.superview viewWithTag:nextTag];
if (nextResponder) {
// Found next responder, so set it.
[nextResponder becomeFirstResponder];
} else {
// Not found, so remove keyboard.
[textField resignFirstResponder];
}
return NO; // We do not want UITextField to insert line-breaks.}SWIFT 4.0
func textFieldShouldReturn(_ textField: UITextField) -> Bool {
let nextTag = textField.tag + 1
// Try to find next responder
let nextResponder = textField.superview?.viewWithTag(nextTag) as UIResponder!
if nextResponder != nil {
// Found next responder, so set it
nextResponder?.becomeFirstResponder()
} else {
// Not found, so remove keyboard
textField.resignFirstResponder()
}
return false}如果文本字段的SuperView將是UITableViewCell，那么下一個(gè)響應(yīng)程序?qū)⑹?/strong>
let nextResponder = textField.superview?.superview?.superview?.viewWithTag(nextTag) as UIResponder!
臨摹微笑
TA貢獻(xiàn)1982條經(jīng)驗(yàn) 獲得超2個(gè)贊
UITextField+Extended.h
@interface UITextField (Extended)@property(retain, nonatomic)UITextField* nextTextField;@end
UITextField+Extended.m
#import "UITextField+Extended.h"#import <objc/runtime.h>static char defaultHashKey;@implementation UITextField (Extended)- (UITextField*)
nextTextField {
return objc_getAssociatedObject(self, &defaultHashKey); }- (void) setNextTextField:(UITextField *)nextTextField{
objc_setAssociatedObject(self, &defaultHashKey, nextTextField, OBJC_ASSOCIATION_RETAIN_NONATOMIC); }@endUITextField *textField1 = ...init your textfieldUITextField *textField2 = ...init your textfieldUITextField *textField3 = ... init your textfield textField1.nextTextField = textField2;textField2.nextTextField = textField3;textField3.nextTextField = nil;
- (BOOL)textFieldShouldReturn:(UITextField *)theTextField {
UITextField *next = theTextField.nextTextField;
if (next) {
[next becomeFirstResponder];
} else {
[theTextField resignFirstResponder];
}
return NO; }- 3 回答
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