為什么python嵌套函數(shù)不稱為閉包？我在Python中看到并使用了嵌套函數(shù)，它們與閉包的定義相匹配。那為什么叫他們nested functions而不是closures?嵌套函數(shù)不是閉包，因?yàn)樗鼈儾粸橥獠渴澜缢脝?？最新情況：我讀到了關(guān)于閉包的文章，它讓我想到了Python的這個(gè)概念。我在下面的評(píng)論中找到了有人提到的那篇文章，但我不能完全理解文章中的解釋，所以我問這個(gè)問題。
3 回答
嗶嗶one
TA貢獻(xiàn)1854條經(jīng)驗(yàn) 獲得超8個(gè)贊
def make_printer(msg):
def printer():
print msg return printer
printer = make_printer('Foo!')printer()make_printerprintermsgprintermsgmake_printer
訪問包含作用域的本地變量， 在超出該范圍的范圍內(nèi)執(zhí)行時(shí)，
def make_printer(msg):
def printer(msg=msg):
print msg return printer
printer = make_printer("Foo!")printer() #Output: Foo!printermsgprintermake_printermsgprinter
墨色風(fēng)雨
TA貢獻(xiàn)1853條經(jīng)驗(yàn) 獲得超6個(gè)贊
function initCounter(){
var x = 0;
function counter () {
x += 1;
console.log(x);
};
return counter;}count = initCounter();count(); //Prints 1count(); //Prints 2count(); //Prints 3def initCounter(): x = 0; def counter (): x += 1 ##Error, x not defined print x return counter count = initCounter();count(); ##Errorcount();count();
更新
1.global
2.nonlocal
3.Object
class Object(object): pass
Object scopeinitCounter
def initCounter (): scope = Object() scope.x = 0 def counter(): scope.x += 1 print scope.x return counter
scopescope
4.x = [0]x[0] += 1x
5.xcounter
def initCounter (): def counter(): counter.x += 1 print counter.x counter.x = 0 return counter
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