TA貢獻(xiàn)1995條經(jīng)驗(yàn) 獲得超2個(gè)贊
>>> import re>>> re.findall("\d+\.\d+", "Current Level: 13.4 db.")['13.4']>>> re.findall(r"[-+]?\d*\.\d+|\d+", "Current Level: -13.2 db or 14.2 or 3")['-13.2', '14.2', '3']
user_input = "Current Level: 1e100 db"for token in user_input.split(): try: # if this succeeds, you have your (first) float print float(token), "is a float" except ValueError: print token, "is something else"# => Would print ...## Current is something else# Level: is something else# 1e+100 is a float# db is something else
TA貢獻(xiàn)1812條經(jīng)驗(yàn) 獲得超5個(gè)贊
>>> import re>>> numeric_const_pattern = r"""
... [-+]? # optional sign
... (?:
... (?: \d* \. \d+ ) # .1 .12 .123 etc 9.1 etc 98.1 etc
... |
... (?: \d+ \.? ) # 1. 12. 123. etc 1 12 123 etc
... )
... # followed by optional exponent part if desired
... (?: [Ee] [+-]? \d+ ) ?
... """>>> rx = re.compile(numeric_const_pattern, re.VERBOSE)>>> rx.findall(".1 .12 9.1 98.1 1. 12. 1 12")
['.1', '.12', '9.1', '98.1', '1.', '12.', '1', '12']>>> rx.findall("-1 +1 2e9 +2E+09 -2e-9")['-1', '+1', '2e9', '+2E+09', '-2e-9']
>>> rx.findall("current level: -2.03e+99db")['-2.03e+99']>>>numeric_const_pattern = '[-+]? (?: (?: \d* \. \d+ ) | (?: \d+ \.? ) )(?: [Ee] [+-]? \d+ ) ?'
rx = re.compile(numeric_const_pattern, re.VERBOSE)rx.findall("Some example: Jr. it. was .23 between 2.3 and 42.31 seconds")
TA貢獻(xiàn)1827條經(jīng)驗(yàn) 獲得超4個(gè)贊
scanf() Token Regular Expression%e, %E, %f, %g [-+]?(\d+(\.\d*)?|\.\d+)([eE][-+]?\d+)?%i [-+]?(0[xX][\dA-Fa-f]+|0[0-7]*|\d+)
\.[.,]
Regular ExpressionInternational float [-+]?(\d+([.,]\d*)?|[.,]\d+)([eE][-+]?\d+)?
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