熊貓-如何平平列中的分級(jí)索引我有一個(gè)數(shù)據(jù)框架,在軸1(列)中有一個(gè)層次索引(來(lái)自groupby.agg行動(dòng)): USAF WBAN year month day s_PC s_CL s_CD s_CNT tempf sum sum sum sum amax amin0 702730 26451 1993 1 1 1 0 12 13 30.92 24.981 702730 26451 1993 1 2 0 0 13 13 32.00 24.982 702730 26451 1993 1 3 1 10 2 13 23.00 6.983 702730 26451 1993 1 4 1 0 12 13 10.04 3.924 702730 26451 1993 1 5 3 0 10 13 19.94 10.94我想把它壓平,使它看起來(lái)像這樣(名字不是關(guān)鍵的-我可以重命名): USAF WBAN year month day s_PC s_CL s_CD s_CNT tempf_amax tmpf_amin 0 702730 26451 1993 1 1 1 0 12 13 30.92 24.981 702730 26451 1993 1 2 0 0 13 13 32.00 24.982 702730 26451 1993 1 3 1 10 2 13 23.00 6.983 702730 26451 1993 1 4 1 0 12 13 10.04 3.924 702730 26451 1993 1 5 3 0 10 13 19.94 10.94我該怎么做?(我試了很多次,但沒(méi)有結(jié)果。)根據(jù)一項(xiàng)建議,這是以DICT的形式出現(xiàn)的頭部。{('USAF', ''): {0: '702730', 1: '702730', 2: '702730', 3: '702730', 4: '702730'}, ('WBAN', ''): {0: '26451', 1: '26451', 2: '26451', 3: '26451', 4: '26451'}, ('day', ''): {0: 1, 1: 2, 2: 3, 3: 4, 4: 5}, ('month', ''): {0: 1, 1: 1, 2: 1, 3: 1, 4: 1}, ('s_CD', 'sum'): {0: 12.0, 1: 13.0, 2: 2.0, 3: 12.0, 4: 10.0}, ('s_CL', 'sum'): {0: 0.0, 1: 0.0, 2: 10.0, 3: 0.0, 4: 0.0}, ('s_CNT', 'sum'): {0: 13.0, 1: 13.0, 2: 13.0, 3: 13.0, 4: 13.0}, ('s_PC', 'sum'): {0: 1.0, 1: 0.0, 2: 1.0, 3: 1.0, 4: 3.0}, ('tempf', 'amax'): {0: 30.920000000000002, 1: 32.0, 2: 23.0, 3: 10.039999999999999, 4: 19.939999999999998}, ('tempf', 'amin'): {0: 24.98, 1: 24.98, 2: 6.9799999999999969, 3: 3.9199999999999982, 4: 10.940000000000001}, ('year', ''): {0: 1993, 1: 1993, 2: 1993, 3: 1993, 4: 1993}}
3 回答

慕雪6442864
TA貢獻(xiàn)1812條經(jīng)驗(yàn) 獲得超5個(gè)贊
df.columns = df.columns.get_level_values(0)
注意:如果to級(jí)別有一個(gè)名稱,您也可以通過(guò)它訪問(wèn)它,而不是0。
.
join
df.columns = [' '.join(col).strip() for col in df.columns.values]
strip
In [11]: [' '.join(col).strip() for col in df.columns.values]Out[11]: ['USAF', 'WBAN', 'day', 'month', 's_CD sum', 's_CL sum', 's_CNT sum', 's_PC sum', 'tempf amax', 'tempf amin', 'year']
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