隨時間移動游戲?qū)ο笪艺趶腟wift SpriteKit背景中學(xué)習(xí)UnityofSpriteKit，其中移動一個精靈的x位置就像運行一個動作一樣直接，如下所示：let moveLeft = SKAction.moveToX(self.frame.width/5, duration: 1.0)let delayAction = SKAction.waitForDuration(1.0)let handSequence = SKAction.
sequence([delayAction, moveLeft])sprite.runAction(handSequence)我想知道一種等效或類似的方法，可以在特定的時間內(nèi)(例如，第二次)將sprite移動到一個特定的位置，并且在UPDATE函數(shù)中不需要調(diào)用這個延遲。
3 回答
幕布斯7119047
TA貢獻1794條經(jīng)驗 獲得超8個贊
WaitForSeconds()Lerp, CoroutineTime.deltaTime
public GameObject objectectA;public GameObject objectectB;void Start(){
StartCoroutine(moveToX(objectectA.transform, objectectB.transform.position, 1.0f));}bool isMoving = false;
IEnumerator moveToX(Transform fromPosition, Vector3 toPosition, float duration){
//Make sure there is only one instance of this function running
if (isMoving)
{
yield break; ///exit if this is still running
}
isMoving = true;
float counter = 0;
//Get the current position of the object to be moved
Vector3 startPos = fromPosition.position;
while (counter < duration)
{
counter += Time.deltaTime;
fromPosition.position = Vector3.Lerp(startPos, toPosition, counter / duration);
yield return null;
}
isMoving = false;}
慕萊塢森
TA貢獻1810條經(jīng)驗 獲得超4個贊
InvokeRepeating
float duration; //duration of movementfloat durationTime; //this will be the value used to check if Time.
time passed the current duration setvoid Start(){
StartMovement();}void StartMovement(){
InvokeRepeating("MovementFunction", Time.deltaTime, Time.deltaTime); //Time.deltaTime is the time passed between two frames
durationTime = Time.time + duration; //This is how long the invoke will repeat}void MovementFunction(){
if(durationTime > Time.time)
{
//Movement
}
else
{
CancelInvoke("MovementFunction"); //Stop the invoking of this function
return;
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