牛魔王的故事
2019-07-02 09:28:42
用MySQL計算中值的簡單方法用MySQL計算中位數(shù)最簡單的方法(希望不是太慢)是什么?我用過AVG(x)但是我很難找到一種簡單的計算中值的方法?,F(xiàn)在,我將所有行返回到PHP,進(jìn)行排序,然后選擇中間行,但肯定有一些簡單的方法可以在一個MySQL查詢中完成。示例數(shù)據(jù):id | val--------
1 4
2 7
3 2
4 2
5 9
6 8
7 3分揀val施予2 2 3 4 7 8 9,所以中值應(yīng)該是4、對決SELECT AVG(val)其中=5.
3 回答

aluckdog
TA貢獻(xiàn)1847條經(jīng)驗 獲得超7個贊
SELECT AVG(dd.val) as median_valFROM (SELECT d.val, @rownum:=@rownum+1 as `row_number`, @total_rows:=@rownum FROM data d, (SELECT @rownum:=0) r WHERE d.val is NOT NULL -- put some where clause here ORDER BY d.val) as ddWHERE dd.row_number IN ( FLOOR((@total_rows+1)/2), FLOOR((@total_rows+2)/2) );
AVG(dd.val)
dd.row_number IN(...)
SELECT FLOOR((3+1)/2),FLOOR((3+2)/2); -- when total_rows is 3, avg rows 2 and 2SELECT FLOOR((4+1)/2),FLOOR((4+2)/2); -- when total_rows is 4, avg rows 2 and 3

GCT1015
TA貢獻(xiàn)1827條經(jīng)驗 獲得超4個贊
對于幾乎所有SQL中的中介: SELECT x.val from data x, data yGROUP BY x.valHAVING SUM(SIGN(1-SIGN(y.val-x.val))) = (COUNT(*)+1)/2
select count(*) from table --find the number of rows
median_row = floor(count / 2)
.
select val from table order by val asc limit median_row,1

慕運維8079593
TA貢獻(xiàn)1876條經(jīng)驗 獲得超5個贊
SELECT x.val from data x, data yGROUP BY x.valHAVING SUM(SIGN(1-SIGN(y.val-x.val)))/COUNT(*) > .5LIMIT 1
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