使用Django和Python創(chuàng)建JSON響應(yīng)我正在嘗試將服務(wù)器端Ajax響應(yīng)腳本轉(zhuǎn)換為Django HttpResponse，但顯然它不起作用。這是服務(wù)器端腳本：/* RECEIVE VALUE */$validateValue=$_POST['validateValue'];$validateId=$_POST['validateId'];$validateError=$_POST['validateError'];/* RETURN VALUE */$arrayToJs = array();$arrayToJs[0] = $validateId;$arrayToJs[1] = $validateError;if($validateValue =="Testuser"){ // Validate??
$arrayToJs[2] = "true"; // RETURN TRUE
echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH success}else{
for($x=0;$x<1000000;$x++){
if($x == 990000){
$arrayToJs[2] = "false";
echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURNS ARRAY WITH ERROR.
}
}}這是轉(zhuǎn)換后的代碼def validate_user(request):
if request.method == 'POST':
vld_value = request.POST.get('validateValue')
vld_id = request.POST.get('validateId')
vld_error = request.POST.get('validateError')
array_to_js = [vld_id, vld_error, False]
if vld_value == "TestUser":
array_to_js[2] = True
x = simplejson.dumps(array_to_js)
return HttpResponse(x)
else:
array_to_js[2] = False
x = simplejson.dumps(array_to_js)
error = 'Error'
return render_to_response('index.html',{'error':error},context_instance=RequestContext(request))
return render_to_response('index.html',context_instance=RequestContext(request))我使用simplejson對(duì)Python列表進(jìn)行編碼(因此它將返回一個(gè)JSON數(shù)組)。我還不知道這個(gè)問題。但我覺得我對(duì)“回聲”做錯(cuò)了什么。
3 回答
慕斯709654
TA貢獻(xiàn)1840條經(jīng)驗(yàn) 獲得超5個(gè)贊
import jsonfrom django.http import HttpResponseresponse_data = {}response_data['result'] = 'error'response_data['message'] = 'Some error message'return HttpResponse(json.dumps(response_data), content_type="application/json")
JsonResponse
from django.http import JsonResponsereturn JsonResponse({'foo':'bar'})
慕勒3428872
TA貢獻(xiàn)1848條經(jīng)驗(yàn) 獲得超6個(gè)贊
from django.http import JsonResponsereturn JsonResponse({'foo':'bar'})
ibeautiful
TA貢獻(xiàn)1993條經(jīng)驗(yàn) 獲得超6個(gè)贊
from django.utils import simplejsonfrom django.http import HttpResponsedef some_view(request):
to_json = {
"key1": "value1",
"key2": "value2"
}
return HttpResponse(simplejson.dumps(to_json), mimetype='application/json')from django.utils import simplejsonclass JsonResponse(HttpResponse): """ JSON response """ def __init__(self, content, mimetype='application/json', status=None, content_type=None): super(JsonResponse, self).__init__( content=simplejson.dumps(content), mimetype=mimetype, status=status, content_type=content_type, )
from django.http import JsonResponsedef some_view(request):
return JsonResponse({"key": "value"})添加回答
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