如何正確分配新的字符串值?我試圖理解如何以最干凈/最安全的方式用C來解決這個瑣碎的問題。下面是我的例子:#include <stdio.h>int main(int argc, char *argv[]){
typedef struct
{
char name[20];
char surname[20];
int unsigned age;
} person;
//Here i can pass strings as values...how does it works?
person p = {"John", "Doe",30};
printf("Name: %s; Age: %d\n",p.name,p.age);
// This works as expected...
p.age = 25;
//...but the same approach doesn't work with a string
p.name = "Jane";
printf("Name: %s; Age: %d\n",p.name,p.age);
return 1;}編譯器的錯誤是:在函數(shù)‘main’中:main.c:18:錯誤:當(dāng)從類型‘char*’分配給類型‘char[20]’時,不兼容類型我知道C(不是C+)沒有字符串類型,而是使用字符數(shù)組,因此另一種方法是修改示例結(jié)構(gòu)以保存字符的指針:#include <stdio.h>int main(int argc, char *argv[]){
typedef struct
{
char *name;
char *surname;
int unsigned age;
} person;
person p = {"John", "Doe",30};
printf("Name: %s; Age: %d\n",p.name,p.age);
p.age = 25;
p.name = "Jane";
printf("Name: %s; Age: %d\n",p.name,p.age);
return 1;}這如預(yù)期的那樣有效,但我不知道是否有更好的方法來做到這一點。謝謝。
3 回答

躍然一笑
TA貢獻1826條經(jīng)驗 獲得超6個贊
strncpy()
strncpy(p.name, "Jane", 19);p.name[19] = '\0'; //add null terminator just in case
strncat()
memcpy()
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