生成v4 UUID的PHP函數(shù)因此，我已經(jīng)做了一些調(diào)查，我一直試圖拼湊一個函數(shù)，以生成一個有效的v4UUID在PHP。這是我能來的最近的一次。我在十六進制、十進制、二進制、PHP的位運算符等方面的知識幾乎是不存在的。此函數(shù)生成一個有效的v4UUID，直到一個區(qū)域。V4 UUID應(yīng)以下形式出現(xiàn)：xxxxxxx-xxxx-4XXX-yxxx-xxxxxxxxxx哪里y是8，9，A或B。這是函數(shù)失敗的地方，因為它不遵守它。我希望在這方面比我有更多知識的人能幫我忙，幫我解決這個問題，這樣它就能遵守這個規(guī)則。職能如下：<?phpfunction gen_uuid() {
$uuid = array(
'time_low' => 0,
'time_mid' => 0,
'time_hi' => 0,
'clock_seq_hi' => 0,
'clock_seq_low' => 0,
'node' => array()
);
$uuid['time_low'] = mt_rand(0, 0xffff) + (mt_rand(0, 0xffff) << 16);
$uuid['time_mid'] = mt_rand(0, 0xffff);
$uuid['time_hi'] = (4 << 12) | (mt_rand(0, 0x1000));
$uuid['clock_seq_hi'] = (1 << 7) | (mt_rand(0, 128));
$uuid['clock_seq_low'] = mt_rand(0, 255);
for ($i = 0; $i < 6; $i++) {
$uuid['node'][$i] = mt_rand(0, 255);
}
$uuid = sprintf('%08x-%04x-%04x-%02x%02x-%02x%02x%02x%02x%02x%02x',
$uuid['time_low'],
$uuid['time_mid'],
$uuid['time_hi'],
$uuid['clock_seq_hi'],
$uuid['clock_seq_low'],
$uuid['node'][0],
$uuid['node'][1],
$uuid['node'][2],
$uuid['node'][3],
$uuid['node'][4],
$uuid['node'][5]
);
return $uuid;}?>感謝任何能幫我的人。
生成v4 UUID的PHP函數(shù)
慕田峪4524236
2019-06-20 11:20:09
