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c#中怎樣獲取js中的變量?

c#中怎樣獲取js中的變量?

C#
肥皂起泡泡 2019-06-07 11:06:55
js: var k = "da";document.getElementById("Hidden2").value = k;cs: Label1.Text = Hidden2.Value;我想問下為什么調(diào)試時(shí),發(fā)現(xiàn)Hidden2.Value是空值?
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2 回答

?
喵喵時(shí)光機(jī)

TA貢獻(xiàn)1846條經(jīng)驗(yàn) 獲得超7個(gè)贊

js調(diào)用后臺(tái)方法和變量
前端javascript腳本
<script language="javascript" type="text/javascript">
// var lpServerIP = "192.168.2.180";//硬盤錄像機(jī)ip
// var lPort = 8001;
// var lpUserName = "admin";
// var lpPassword = "12345";
// var lChannelNum = 2;

var lpServerIP = "<%=getIpServerIP()%>";//硬盤錄像機(jī)ip
var lPort = "<%=iPort %>";
var lpUserName = "<%=getlpUserName()%>";
var lpPassword = "<%=getlpPassword()%>";
var lChannelNum = "<%=iChannelNum %>";
var UserID

function Play()
{
var i;
var Netocx = document.getElementById("NetOCX");
UserID = Netocx.Login(lpServerIP,lPort,lpUserName,lpPassword);
i = Netocx.StartRealPlay(lChannelNum,0, 0);
if (i == 0)
{
alert("預(yù)覽失敗!");
}
}
function Stop()
{
var Netocx = document.getElementById("NetOCX");
Netocx.StopRealPlay();
Netocx.Logout();
}
function FullScreen()
{
var Netocx = document.getElementById("NetOCX");
Netocx.FullScreenCtrl();
}
function Play1()
{
var Netocx1 = document.getElementById("NetOCX1");
UserID = Netocx1.Login("172.7.76.85",8000,"admin","12345");
Netocx1.StartRealPlay(0 ,0, 0);
}
function Stop1()
{
var Netocx1 = document.getElementById("NetOCX1");
Netocx1.StopRealPlay();
Netocx1.Logout();
}

</script>



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反對(duì) 回復(fù) 2019-06-08
?
BIG陽

TA貢獻(xiàn)1859條經(jīng)驗(yàn) 獲得超6個(gè)贊

沒問題啊:(注意script的位置)
<body>
<form id="form1" runat="server">
<div>
<asp:HiddenField ID="HiddenField1" runat="server" />
<asp:Label ID="Label1" runat="server" Text="Label"></asp:Label>
<asp:Button ID="Button1" runat="server" Text="Button" onclick="Button1_Click" />
</div>
</form>
<script type="text/javascript">
var k = "Pa";
document.getElementById("HiddenField1").value = k;
</script>
</body>
單擊Button1時(shí) Label1顯示為Pa
后臺(tái)代碼:

protected void Button1_Click(object sender, EventArgs e)
{
this.Label1.Text = HiddenField1.Value;
}



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反對(duì) 回復(fù) 2019-06-08
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