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怎么用javascript語(yǔ)言編程一個(gè)愛心形狀呢 ?

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夢(mèng)里花落0921 2019-05-29 21:07:07

怎么用javascript語(yǔ)言編程一個(gè)愛心形狀呢

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4 回答

侃侃爾雅

TA貢獻(xiàn)1801條經(jīng)驗(yàn) 獲得超16個(gè)贊

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<!doctype html>

<html>

<head>

<meta charset="UTF-8">

<title>Untitled Document</title>

</head>

<body>

<p style="text-align:center"><canvas id="canvas1" height="600" width="600"></canvas></p>

<script type="text/javascript">

var canvas = document.getElementById("canvas1");

var ctx = canvas.getContext("2d");

ctx.translate(300,300); //sets center in the middle of the picture

drawHeart();

function drawHeart() {

ctx.beginPath();

ctx.moveTo(0,-100);

ctx.bezierCurveTo(120,-300, 300,-100, 200,50);

ctx.lineTo(0,250);

ctx.lineTo(-200,50);

ctx.bezierCurveTo(-300,-100, -120,-300, 0,-100);

ctx.closePath();

ctx.fillStyle="#ff0000";

ctx.fill();

}

</script>

</body>

</html>

反對(duì) 回復(fù) 2019-06-01

慕的地10843

TA貢獻(xiàn)1785條經(jīng)驗(yàn) 獲得超8個(gè)贊

你自己要改一下，輸出位置為一個(gè)空格的全部改成兩個(gè)，其他的不用改）：

實(shí)心的：
#include<stdio.h>
int n;
void draw(int n)
{
int i,j;
for (i=1-(n>>1);i<=n;i++)
if (i>=0)
{
for (j=0;j<i;j++) printf(" ");
for (j=1;j<=2*(n-i)+1;j++) printf(" *");
printf("\n");
}
else
{
for (j=i;j<0;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++) printf(" *");
for (j=1;j<=-1-2*i;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++) printf(" *");
printf("\n");
}
}
int main()
{
printf("Please input the size (n>=4):");
scanf("%d",&n);
draw(n);
return 0;
}

空心的：
#include<stdio.h>
int n;
void draw(int n)
{
int i,j;
for (i=1-(n>>1);i<=n;i++)
if (i>0)
{
for (j=0;j<i;j++) printf(" ");
for (j=1;j<=2*(n-i)+1;j++)
if (j==1||j==2*(n-i)+1) printf(" *");
else printf(" ");
printf("\n");
}
else
if (i==0)
{
printf(" *");
for (j=1;j<n;j++) printf(" ");
printf(" *");
for (j=1;j<n;j++) printf(" ");
printf(" *\n");
}
else
{
for (j=i;j<0;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++)
if (i==1-(n>>1)) printf(" *");
else if (j==1||j==n+2*i+1) printf(" *");
else printf(" ");
for (j=1;j<=-1-2*i;j++) printf(" ");
for (j=1;j<=n+2*i+1;j++)
if (i==1-(n>>1)) printf(" *");
else if (j==1||j==n+2*i+1) printf(" *");
else printf(" ");
printf("\n");
}
}
int main()
{
printf("Please input the size (n>=4):");
scanf("%d",&n);
draw(n);
return 0;
}

反對(duì) 回復(fù) 2019-06-01

森欄

TA貢獻(xiàn)1810條經(jīng)驗(yàn) 獲得超5個(gè)贊

/*
用C語(yǔ)言輸出：
* *
* * *
* *
*

*/

#include <stdio.h>

int main()
{
int a[4][7] ={{0,1,0,0,0,1,0},{1,0,0,1,0,0,1},{0,1,0,0,0,1,0},{0,0,0,1,0,0,0}};
for(int i=0;i<4;i++) /*輸出行*/
{
for(int j=0;j<7;j++) /*輸出列*/
{
if(a[i][j] !=0)
printf("*");
else
printf(" ");
}
printf("\n");
}

return 0;
}
//這是我用索引數(shù)組的方法寫的。