3 回答

TA貢獻(xiàn)1829條經(jīng)驗(yàn) 獲得超6個(gè)贊
#include <cstdlib>
#include <iostream>
#include <cmath>
using namespace std;
int main(int argc,char *argv[])
{
char ch;
for(int i=0;;i++)
{
cout <<"Enter:(Y-continue,N-exit):";
cin >>ch;
if(ch == 'N')
{
return 0;
}
else if(ch == 'Y')
{
continue; //換成要執(zhí)行的代碼
}
}
system("PAUSE");
return EXIT_SUCCESS;
}

TA貢獻(xiàn)1844條經(jīng)驗(yàn) 獲得超8個(gè)贊
這樣:
char a = 'Y';
...
do
{
...
cout<<"please input 'Y' or 'N'";
}whlie(getchar() == a);

TA貢獻(xiàn)1752條經(jīng)驗(yàn) 獲得超4個(gè)贊
#include<iostream>
using namespace std;
int main(void)
{
char b;
start:
{printf("輸入(y/n):");
scanf("%c",&b);
getchar();
}
if(b=='y')
goto start;
else
return 0;
}
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