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c++編程，給出年月日，計(jì)算該日是該年的第幾天？

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紅糖糍粑 2019-05-23 19:15:15

c++編程，給出年月日，計(jì)算該日是該年的第幾天

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3 回答

紅顏莎娜

TA貢獻(xiàn)1842條經(jīng)驗(yàn) 獲得超13個(gè)贊

1	#include <iostream>

1	using namespace std;

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int main()

{

int sum_day(int month,int day);

int is_leap(int year);

int year,month,day,days;

1 2	cout<<"Enter date(for example:2015 1 14):\n"; cin>>year>>month>>day;

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days=sum_day(month,day);

if(is_leap(year)&&month>2)

days+=1;

1	cout <<year<<"/"<<month<<"/"<<day<<"is the "<<days<<" day in this year!\n";

1 2	return 0; }

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int sum_day(int month,int day)

{

int day_tab[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};

int i;

for(i=1;i<month;i++)

day+=day_tab[i];

return day;

}

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int is_leap(int year)

{

return ((year%4==0&&year%100!=0) ||year%400==0);

}

我在code blocks上運(yùn)行沒有問題

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慕桂英546537

TA貢獻(xiàn)1848條經(jīng)驗(yàn) 獲得超10個(gè)贊

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#include<iostream>

using namespace std;

int d[2][12]={{31,28,31,30,31,30,31,31,30,31,30,31},

{31,29,31,30,31,30,31,31,30,31,30,31} };

int days(int m,int a=0)

{

int sumday=0;

for(int i=0;i<m-1;++i)

sumday+=d[a][i];

return sumday;

}

int main()

{

int day=0,month=0,year=0;

cout<<"day :";cin>>day;

cout<<"month :";cin>>month;

cout<<"year :";cin>>year;

int a=0;

// 閏年判斷

if((year%4==0&&year%100!=0)||year%400==0)a=1;

switch(month)

{

case 1:case 2:

case 3:case 4:

case 5:case 6:

case 7:case 8:

case 9:case 10:

case 11:case 12: cout<<days(month,a)+day<<endl;

default: break;

}

return 0;

}

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互換的青春

TA貢獻(xiàn)1797條經(jīng)驗(yàn) 獲得超6個(gè)贊

# include <stdio.h>

# include <conio.h>

int sum_day(int month, int day);

int leap(int year);

void main()

{

int year, month, day;

int days;

printf("請(qǐng)輸入日期(年，月，日)：");

scanf("%d, %d, %d", &year, &month, &day);

printf("%d年%d月%d日", year, month, day);

days = sum_day(month, day);

if(leap(year) && month>=3)

days = days + 1;

printf("是該年的第%d天.\n", days);

getch();

}

static int day_tab[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int sum_day(int month, int day)

{

int i;

for(i=1; i<month; i++)

day = day + day_tab[i];

return day;

}

int leap(int year)

{

int leap;

leap = (year%4==0&&year%100!=0)||(year%400==0);

return leap;

}

沒調(diào)試過，機(jī)子上暫時(shí)沒工具，應(yīng)該是沒問題了。你試試