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JS數(shù)組格式合并轉(zhuǎn)換

JS數(shù)組格式合并轉(zhuǎn)換

有如下數(shù)組varsourceList=[{SupportProgramId:1,Category:"AAA",SubCategory:"A-1"},{SupportProgramId:2,Category:"AAA",SubCategory:"A-2"},{SupportProgramId:3,Category:"AAA",SubCategory:"A-3"},{SupportProgramId:4,Category:"BBB",SubCategory:"B-1"},{SupportProgramId:5,Category:"CCC",SubCategory:"C-1"},{SupportProgramId:6,Category:"CCC",SubCategory:"C-2"}];要求轉(zhuǎn)換成如下格式:[{mainTitle:"AAA"subList:[{subId:1subTitle:"A-1"},{subId:2subTitle:"A-2"},{subId:3subTitle:"A-3"}]},{mainTitle:"BBB"subList:[{subId:4subTitle:"B-1"}]},{mainTitle:"CCC"subList:[{subId:5subTitle:"C-1"},{subId:6subTitle:"C-2"}]}]求好的轉(zhuǎn)換過(guò)程,可以使用es6或lodash提供的方法
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2 回答

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供參考
vardata=Array.from(sourceList.reduce((map,{
SupportProgramId:subId,Category:mainTitle,SubCategory:subTitle
})=>{
if(map.has(mainTitle)){
map.get(mainTitle).subList.push({subId,subTitle})
}else{
map.set(mainTitle,{mainTitle,subList:[{subId,subTitle}]})
}
returnmap
},newMap()).entries())
                            
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functionconvert(arr){
varexists={}
varresult=[]
arr.forEach(v=>{
if(exists[v.Category]){
exists[v.Category].push({
subId:v.SupportProgramId,
subTitle:v.SubCategory
})
}else{
exists[v.Category]=[{
subId:v.SupportProgramId,
subTitle:v.SubCategory
}]
}
})
for(varkeyinexists){
result.push({
mainTitle:key,
subList:exists[key]
})
}
returnresult
}
//...
console.log(convert([
{SupportProgramId:1,Category:"AAA",SubCategory:"A-1"},
{SupportProgramId:2,Category:"AAA",SubCategory:"A-2"},
{SupportProgramId:3,Category:"AAA",SubCategory:"A-3"},
{SupportProgramId:4,Category:"BBB",SubCategory:"B-1"},
{SupportProgramId:5,Category:"CCC",SubCategory:"C-1"},
{SupportProgramId:6,Category:"CCC",SubCategory:"C-2"}
]))
                            
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反對(duì) 回復(fù) 2019-05-25
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