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關(guān)于Php數(shù)組的問(wèn)題

關(guān)于Php數(shù)組的問(wèn)題

陪伴而非守候 2019-05-23 19:17:18
Array([0]=>Array([oid]=>190[color]=>[goods_name]=>測(cè)試要[goods_num]=>1[goods_price]=>0.01[id]=>44[img]=>/Public/Uploads/2017-12-13/5a30fa5763bdb.jpg[user_openid]=>oWWUP0dieOLSHl3CzjyHIcIdhtVo[order_number]=>20181513226463[tid]=>92[status]=>1[tuiid]=>[aid]=>[gid]=>[corm_time]=>1514862004)[1]=>Array([oid]=>191[color]=>[goods_name]=>A5筆記本子[goods_num]=>2[goods_price]=>0.01[id]=>43[img]=>/Public/Uploads/2017-12-06/5a27add5325d1.jpg[user_openid]=>oWWUP0dieOLSHl3CzjyHIcIdhtVo[order_number]=>20181513241259[tid]=>93[status]=>1[tuiid]=>[aid]=>[gid]=>[corm_time]=>1514862004)[2]=>Array([oid]=>193[color]=>[goods_name]=>測(cè)試要[goods_num]=>1[goods_price]=>0.01[id]=>46[img]=>/Public/Uploads/2017-12-13/5a30fa5763bdb.jpg[user_openid]=>oWWUP0dieOLSHl3CzjyHIcIdhtVo[order_number]=>20181513241259[tid]=>93[status]=>1[tuiid]=>[aid]=>[gid]=>[corm_time]=>1514862004))如上數(shù)組是$a;我需求出上面數(shù)組的goods_num之和最終組合成下面這個(gè)樣的數(shù)組,請(qǐng)大神們幫個(gè)忙吧!Array([0]=>Array([name]=>測(cè)試要[number]=>2)[1]=>Array([name]=>A5筆記本子[number]=>2))完全沒(méi)有頭緒,也不知道怎么搞。。。。反正就是各種懵逼了?。?!~我通過(guò)直接在數(shù)據(jù)庫(kù)計(jì)算,出現(xiàn)這樣的結(jié)果Array([0]=>Array([name]=>測(cè)試要[number]=>2)[1]=>Array([name]=>A5筆記本子[number]=>2)[2]=>Array([name]=>測(cè)試要[number]=>2))但是去重又是個(gè)問(wèn)題了。我實(shí)在不知道咋搞了。。還是得求大神?。。?!
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2 回答

?
Helenr

TA貢獻(xiàn)1780條經(jīng)驗(yàn) 獲得超4個(gè)贊

假設(shè)你的商品表為goods
selectgoods_nameasname,sum(goods_num)asnumberfromgoodsgroupbyname;
                            
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?
PIPIONE

TA貢獻(xiàn)1829條經(jīng)驗(yàn) 獲得超9個(gè)贊

$arr=[
['goods_name'=>'a','goods_num'=>1],
['goods_name'=>'b','goods_num'=>1],
['goods_name'=>'c','goods_num'=>1],
['goods_name'=>'a','goods_num'=>2],
['goods_name'=>'a','goods_num'=>3],
['goods_name'=>'a','goods_num'=>5],
['goods_name'=>'a','goods_num'=>8],
['goods_name'=>'b','goods_num'=>8],
['goods_name'=>'d','goods_num'=>9],
];
$arr=array_reduce($arr,function($group,$item){
$group[$item['goods_name']][]=$item['goods_num'];
return$group;
},[]);
$arr=array_map(function($i){
returnarray_sum($i);
},$arr);
print_r($arr);
                            
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反對(duì) 回復(fù) 2019-05-23
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