首頁猿問兩個數(shù)組比較的問題

兩個數(shù)組比較的問題

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梵蒂岡之花 2019-05-20 17:23:48

數(shù)組a：[{"user_num":"75925","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75921","MeterNo":"50005445","BookNo":"51010"},{"user_num":"7595","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75984","MeterNo":"50005445","BookNo":"51010"},{"user_num":"759020","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75930","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75911","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75931","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75912","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75932","MeterNo":"50005445","BookNo":"51010"},{"user_num":"75913","MeterNo":"50005445","BookNo":"51010"}]數(shù)組b:[{user_num:75925,name:"范小明"},{user_num:75921,name:"李大霄"},{user_num:7595,name:"劉士雨"},{user_num:75984,name:"廖冰"},{user_num:7598020,name:"李剛"},{user_num:7597,name:"李世民"},{user_num:75930,name:"劉彬彬"},{user_num:75911,name:"森美"}]我想得到這樣的效果，遍歷數(shù)組a的user_num，如果，其值在數(shù)組b里，則取出該數(shù)組b的name屬性，并添加到數(shù)組a中。如果user_num沒有在數(shù)組b中，在添加一個默認值name屬性(可以設(shè)為default)給數(shù)組a.最后，數(shù)組a將變成這樣：[{"user_num":"75925","MeterNo":"50005445","BookNo":"51010","name":"范小明"},{"user_num":"75921","MeterNo":"50005445","BookNo":"51010","name":"李大霄"},{"user_num":"7595","MeterNo":"50005445","BookNo":"51010","name":"劉士雨"},{"user_num":"75984","MeterNo":"50005445","BookNo":"51010","name":"廖冰"},{"user_num":"759020","MeterNo":"50005445","BookNo":"51010","name":"李剛"},{"user_num":"75930","MeterNo":"50005445","BookNo":"51010","name":"劉彬彬"},{"user_num":"75911","MeterNo":"50005445","BookNo":"51010","name":"森美"},{"user_num":"75931","MeterNo":"50005445","BookNo":"51010","name":"default"},{"user_num":"75912","MeterNo":"50005445","BookNo":"51010","name":"default"},{"user_num":"75932","MeterNo":"50005445","BookNo":"51010","name":"default"},{"user_num":"75913","MeterNo":"50005445","BookNo":"51010","name":"default"}]

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2 回答

斯蒂芬大帝

TA貢獻1827條經(jīng)驗獲得超8個贊

functionassign(a,b){for(leti=0,len=a.length;ifor(letj=0,len=b.length;jif(parseInt(a[i].user_num)===parseInt(b[j].user_num)){a[i].name=b[j].name;break;}else{a[i].name='default';}}}returna}

反對回復(fù) 2019-05-20

LEATH

TA貢獻1936條經(jīng)驗獲得超7個贊

樓上代碼其實有缺陷沒有必要不相等就給a[i].name賦值為default應(yīng)該是第二個for循環(huán)走完了如果a[i].name沒有值，才進行賦值。functionassign(a,b){for(leti=0,len=a.length;ifor(letj=0,len=b.length;jif(parseInt(a[i].user_num)===parseInt(b[j].user_num)){a[i].name=b[j].name;break;}}if(a[i].name){a[i].name='default';}}returna}