leta=[{name:"1",status:"1"},{name:"2",status:"1"},{name:"3",status:"2"},{name:"4",status:"2"},{name:"5",status:"3"},{name:"6",status:"bbb"}]{'1':[{name:"1",status:"1"},{name:"2",status:"1"}],'2':[{name:"3",status:"2"},{name:"4",status:"2"}],'3':[{name:"5",status:"3"}],'bbb':[{name:"6",status:"bbb"}]}用ES6如何把上面的變成下面這種結(jié)構(gòu),萌新求救。就是把status提出來當(dāng)下面的鍵值。
一個(gè)簡單的數(shù)組問題，ES6如何優(yōu)雅的解決，萌新求救
函數(shù)式編程
2019-05-20 17:13:09
