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js多個數(shù)組(3個以上)如何合并成json形式

JavaScript

紅糖糍粑 2019-05-11 15:34:31

題目描述arr1=[1,2,3,4,5];arr2=[a1,a2,a3,a4,a5];arr3=[b1,b2,b3,b4,b5];arr4=[c1,c2,c3,c4,c5];arr5=[11,22,33,44,55];多個數(shù)組類似這個形式，數(shù)組里內(nèi)容是不定的需要合并成這個形式[{"a":"1","b":"a1","c":"b1","d":"c1","e":"11"},{"a":"2","b":"a2","c":"b2","d":"c2","e":"22"},{"a":"3","b":"a3","c":"b3","d":"c3","e":"33"},{"a":"4","b":"a4","c":"b4","d":"c4","e":"44"},{"a":"5","b":"a5","c":"b5","d":"c5","e":"55"}]兩個數(shù)組我用的2個for循環(huán)嵌套和if語句判斷push到對象里如果更多(5-6個數(shù)組)有什么更好的辦法。

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3 回答

weixin_慕仰3408494

TA貢獻(xiàn)1條經(jīng)驗獲得超0個贊

大佬你這問題解決了嗎? 我也遇到這問題了

反對回復(fù) 2020-03-20

夢里花落0921

TA貢獻(xiàn)1772條經(jīng)驗獲得超6個贊

動態(tài)傳入數(shù)組，動態(tài)計算key，即可，代碼如下：constarr1=[1,2,3,4,5];constarr2=['a1','a2','a3','a4','a5'];constarr3=['b1','b2','b3','b4','b5'];constarr4=['c1','c2','c3','c4','c5'];constarr5=[11,22,33,44,55];functionparse(...arrList){constresult=[]for(leti=0,l=arrList.length,arr,key;iarr=arrList[i]key=String.fromCharCode(97+i)for(letj=0,l=arr.length;jif(!result[j]){result[j]={}}result[j][key]=arr[j]}}returnresult}parse(arr1,arr2,arr3,arr4,arr5)

反對回復(fù) 2019-05-11

汪汪一只貓

TA貢獻(xiàn)1898條經(jīng)驗獲得超8個贊

看錯問題，再修改一下:import_from'lodash'constarr1=[1,2,3,4,5];constarr2=['a1','a2','a3','a4','a5'];constarr3=['b1','b2','b3','b4','b5'];constarr4=['c1','c2','c3','c4','c5'];constarr5=[11,22,33,44,55];constresult=_.zip(arr1,arr2,arr3,arr4,arr5)console.log(result)