在應(yīng)用程序打開之前 XMLParser 就崩潰了。錯(cuò)誤是：org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:137)XMLParser 代碼：public class XMLParser {
public XMLParser(){
}
public String getXmlFromUrl(String url){
String xml = null;
try{
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e){
e.printStackTrace();
} catch (ClientProtocolException e){
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return xml;
}
public Document getDomElement(String xml){
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try{
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch(ParserConfigurationException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (SAXException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (IOException e) {
Log.e("Error: ", e.getMessage());
return null;
}
return doc;
}在 main activity 中是這樣調(diào)用的：XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL);
Document doc = parser.getDomElement(xml);所以問(wèn)題出在哪里呢？
3 回答
幕布斯6054654
TA貢獻(xiàn)1876條經(jīng)驗(yàn) 獲得超7個(gè)贊
LZ的網(wǎng)絡(luò)請(qǐng)求返回都不用判斷狀態(tài)？直接就調(diào)用 HttpEntity httpEntity = httpResponse.getEntity();xml = EntityUtils.toString(httpEntity);
？？？
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