我想在數(shù)據(jù)庫(kù)中放入一個(gè)entry。用的下面的代碼：String url = String.format("http://xxxxxxx/xxx/index.php?home=yes&pid=%s", pid);         // Create a new HttpClient and Post Header         HttpClient httpclient = new DefaultHttpClient();         HttpPost httppost = new HttpPost(url);     try {         ResponseHandler<String> responseHandler = new BasicResponseHandler();         String response = httpclient.execute(httppost, responseHandler);          Log.e("abc", response);         return response;         } catch (ClientProtocolException es)          {                Log.e("x" , es.getMessage());             return "";         } catch (IOException e)          {             Log.e("aasx" , e.getMessage());             return "";         }這段代碼能正常運(yùn)行，現(xiàn)在當(dāng)有網(wǎng)絡(luò)連接的時(shí)候，代碼就會(huì)困在httpclient.execute(httppost, responseHandler); 大約倆分鐘。有什么方法可以實(shí)現(xiàn)檢查幾秒鐘后，如果沒(méi)有反應(yīng)的就會(huì)就catch the exceptions?