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js判斷兩個(gè)數(shù)組的值是否相等值的順序可能不同

JavaScript

慕妹3242003 2019-04-27 22:20:06

請(qǐng)問有什么好的辦法可以判斷兩個(gè)數(shù)組的值是否相等嗎比如：a=['a','b','c','d'];b=['b','c','d','a'];順序不同但是只要值是相同的話就返回true就可以了謝謝大家

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繁花不似錦

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functionf(a,b){m=newMap()a.forEach(o=>m.set(o,(m.get(o)||0)+1));b.forEach(o=>m.set(o,(m.get(o)||0)-1));for(varvalueofm.values()){if(value!==0){returnfalse}}returntrue}

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皈依舞

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isContained=(a,b)=>{if(!(ainstanceofArray)||!(binstanceofArray))returnfalse;if(a.length!=b.length)returnfalse;for(vari=0,len=b.length;iif(a.indexOf(b[i])==-1&&b.indexOf(a[i])==-1){returnfalse;}}returntrue;}arr1=[1,2,3,4,'obj'];arr2=[4,3,2,1,'obj'];alert(isContained(arr1,arr2));如果不習(xí)慣箭頭函數(shù)：functionisContained(a,b){if(!(ainstanceofArray)||!(binstanceofArray))returnfalse;if(a.length!=b.length)returnfalse;for(vari=0,len=b.length;iif(a.indexOf(b[i])==-1&&b.indexOf(a[i])==-1){returnfalse;}}returntrue;}arr1=[1,2,3,4,'obj'];arr2=[4,3,2,1,'obj'];alert(isContained(arr1,arr2));