首頁猿問求一個(gè)js正則表達(dá)式

求一個(gè)js正則表達(dá)式

JavaScript

慕工程0101907 2019-04-14 09:52:55

檢索一個(gè)json字符串;格式:varjson='[{"i":"t2","n":"xx","x":"12678","y":"10456","c":"","m":3},{"i":"t3","n":"xx","x":"13678","y":"11456","c":"","m":3},{"i":"t4","n":"xx","x":"18456","y":"13456","c":"","m":3}]';//條件11000

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2 回答

GCT1015

TA貢獻(xiàn)1827條經(jīng)驗(yàn) 獲得超4個(gè)贊

試試json.match(/\{[^{]+?\"x\":\"1[12][0-9]{3}\",\"y\":\"1[12][0-9]{3}\",[^}]+?\}/g)？看看我有沒有寫錯(cuò)/\{[^{]+?//排除{，使用惰性匹配\"x\":\"1[12][0-9]{3}\",//只匹配x從11000到12999的內(nèi)容\"y\":\"1[12][0-9]{3}\",[^}]+?\}/g//作用于全局

反對回復(fù) 2019-04-14

大話西游666

TA貢獻(xiàn)1817條經(jīng)驗(yàn) 獲得超14個(gè)贊

沒必要用正則啊。js處理json最合適不過了。varjson='[{"i":"t2","n":"xx","x":"12678","y":"10456","c":"","m":3},{"i":"t3","n":"xx","x":"13678","y":"11456","c":"","m":3},{"i":"t4","n":"xx","x":"18456","y":"13456","c":"","m":3}]';//條件11000vardata=JSON.parse(json);varresult=[];data.forEach(function(item){if(item.x>11000&&item.x<13000&&item.y>11000&&item.y<13000){console.log(item);result.push(item);}});