ruby怎么實(shí)現(xiàn)數(shù)組減法
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irb(main):001:0> a=[1,2,5,3,9,0,9]
=> [1, 2, 5, 3, 9, 0, 9]
irb(main):002:0> a-[2]
=> [1, 5, 3, 9, 0, 9]
irb(main):004:0> a
=> [1, 2, 5, 3, 9, 0, 9]
irb(main):005:0> a-[4]
=> [1, 2, 5, 3, 9, 0, 9]
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