$arr=array(array('id'=>1,'user_name'=>'test1'),array('id'=>2,'user_name'=>'test2'),array('id'=>3,'user_name'=>'test3'));$arr2=array(array('id'=>1,'shop_name'=>'shop1'),array('id'=>5,'shop_name'=>'shop2'),array('id'=>3,'shop_name'=>'shop3'));怎么根據(jù)2個(gè)數(shù)組id相同的一維數(shù)組，將$arr2的shop_name添加到$arr，如果沒(méi)有相同的id，shop_name為空，形成如下數(shù)組：$good_arr=array(array('id'=>1,'user_name'=>'test1','shop_name'=>'shop1'),array('id'=>2,'user_name'=>'test2','shop_name'=>''),array('id'=>3,'user_name'=>'test3','shop_name'=>'shop3'));我的方案：有更好的嗎？O(∩_∩)O謝謝/*foreach($arras$key=>&$value){$value['shop_name']='';}unset($value);*/foreach($arras$k2=>&$v2){$v2['shop_name']='';foreach($arr2as$k=>$v){if($v2['id']==$v['id']){$v2['shop_name']=$v['shop_name'];}}}print_r($arr);